A. The horizontal velocity is
vx = dx/dt = π - 4πsin (4πt + π/2)
vx = π - 4π sin (0 + π/2)
vx = π - 4π (1)
vx = -3π
b. vy = 4π cos (4πt + π/2)
vy = 0
c. m = sin(4πt + π/2) / [<span>πt + cos(4πt + π/2)]
d. m = </span>sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]
e. t = -1.0
f. t = -0.35
g. Solve for t
vx = π - 4πsin (4πt + π/2) = 0
Then substitute back to solve for vxmax
h. Solve for t
vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax
i. s(t) = [<span>x(t)^2 + y</span>(t)^2]^(1/2)
h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt
k and l. Solve for the values of t
d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
And substitute to determine the maximum and minimum speeds.
Answer:
1.77 x 10^-8 C
Explanation:
Let the surface charge density of each of the plate is σ.
A = 4 x 4 = 16 cm^2 = 16 x 10^-4 m^2
d = 2 mm
E = 2.5 x 10^6 N/C
ε0 = 8.85 × 10-12 C2/N ∙ m2
Electric filed between the plates (two oppositively charged)
E = σ / ε0
σ = ε0 x E
σ = 8.85 x 10^-12 x 2.5 x 10^6 = 22.125 x 10^-6 C/m^2
The surface charge density of each plate is ± σ / 2
So, the surface charge density on each = ± 22.125 x 10^-6 / 2
= ± 11.0625 x 10^-6 C/m^2
Charge on each plate = Surface charge density on each plate x area of each plate
Charge on each plate = ± 11.0625 x 10^-6 x 16 x 10^-4 = ± 1.77 x 10^-8 C
Answer:
24.348mm
Explanation:
NB: I'll be attaching pictures so as to depict missing mathematical expressions or special characters which are not easily found on keyboards
K = d / €^n
Note : d represents the greek alphabet epsilion.
K = 345 / 0.02⁰.²² = 816mPa
The true strain based upon the stress of 414mPa =
€= (€/k)^1/n = (414/816)¹/⁰.²² = 0.04576
However the true relationship between true strain and length is given by
€ = ln(Li/Lo)
Making Li the subject of formula by rearranging,
Li = Lo.e^€
Li = 520e⁰.⁰⁴⁵⁷⁶
Li = 544.348mm
The amount of elongation can be calculated from
Change in L = Li - Lo = 544.348 - 520 change in L = 24.348mm.
Answer:
They two waves has the same amplitude and frequency but different wavelengths.
Explanation: comparing the wave equation above with the general wave equation
y(x,t) = Asin(2Πft + 2Πx/¶)
Let ¶ be the wavelength
A is the amplitude
f is the frequency
t is the time
They two waves has the same amplitude and frequency but different wavelengths.
Answer:
45 meters
Explanation:
20 min = 15 meters
So if 20 x 3 = 60
you have to do 3 x 15 !
- which equals to 45 <3
<u>- mark me brainlest pls . </u>
