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Ket [755]
2 years ago
13

Eric bought a ruler for $1.29 and an eraser for $0.39. He paid with $2.00. What is the correct amount of change he should get ba

ck?
1. quarter dime Nickel and 2 pennies
2. Quarter nickel 2 pennies
3.2 dimes and two pennies
4. Nickel dime 2 pennies
Mathematics
1 answer:
Gelneren [198K]2 years ago
4 0
It would be answer choice 2
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We flip a fair coin five times. For every heads you pay me $1 and for every tails I pay you $1. Let X denote the my net winning
TEA [102]

Answer:

The probability mass of X is 0.03

Step-by-step explanation:

If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.

Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.

Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.

The probability of winning start to drop as the winning amount increases.

       

     X                          0     1               2     3       4      5

Probability of Heads  0 0.50 0.25 0.13    0.06 0.03

8 0
2 years ago
The angle measures associated with which set of ordered pairs share the same reference angle
Trava [24]

Answer:

Option 3 is right.

Step-by-step explanation:

Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.

In whatever way we find reference angles,

cos will remain cos only and sin will remain sin only there may be only changes in sign.

Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos.  Hence these options cannot be for reference angles.

III option is (-\frac{1}{2} ,\frac{-\sqrt{3} }{2} )(\frac{1}{2} ,\frac{\sqrt{3} }{2} )

show that both sign and cos changed sign.  This is possible only in III quadrant.

ie reference angle of orignal angle t = 180+t

SO this option is right.

7 0
2 years ago
Read 2 more answers
In a camp there is food for 400 persons for 23 days-if 60 more persons join the camp find the number of days the provision will
Deffense [45]

The answer is 20 days.

After 60 people have joined there will be 460 people in the camp.

The number of days which the provisions will last will be proportional less after the 60 people have joined and will be:-

(400/460) * 23

= (20 / 23) * 23

=  20


3 0
2 years ago
Which polynomial is prime? x3 + 3x2 – 2x – 6 x3 – 2x2 + 3x – 6 4x4 + 4x3 – 2x – 2 2x4 + x3 – x + 2
alexandr1967 [171]
D. 2x4+x3–x+2 <span>is prime</span>
4 0
2 years ago
Read 2 more answers
The sum of Jim's weight and Bob's weight is 180 pounds. If you subtract Jim's weight from Bob's weight, you get half of Bob's we
Furkat [3]

Answer:

120 pounds

Step-by-step explanation:

We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:

j + b = 180

b - j = 1/2b

Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)

b - j = \frac{b}{2}\\\frac{b}{2} - j = 0

Now we can solve using the process of elimination.

b + j = 180\\\\\frac{b}{2} - j = 0\\\\b + \frac{b}{2} = 180\\\\b + b \cdot 2 = 180\cdot 2\\3b = 360\\b = 120

Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.

120 + j = 180\\j = 180-120\\j = 60

So Bob weighs 120 pounds and Jim weight 60 pounds.

Hope this helped!

4 0
2 years ago
Read 2 more answers
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