Answer:
The Answer Is (C.)
Step-by-step explanation:
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Answer:
what's the rest of the question
Step-by-step explanation:
:/
Answer:
Volume of the right pyramid = 288 m²
Step-by-step explanation:
Volume of the pyramid = 
From the ΔAOB,
By Pythagoras theorem,
AB² = AO² + OB²
(6√2)² = AO² + (6)²
72 = AO² + 36
AO = √(36) = 6 m
Since base of the pyramid is a square so area of the base = (Length × Width) = (side)²
Now volume of the pyramid = ![\frac{1}{3}[(Length)(width)]\times height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%5B%28Length%29%28width%29%5D%5Ctimes%20height)
= 
= 288 m²
Therefore, volume of the right pyramid is 288 m².
Answer:
(9a^2b^2(2ab - 3b + 4a).
Step-by-step explanation:
Take out the GCF.
The GCF is 9a^2b^2 so the factors are
(9a^2b^2(2ab - 3b + 4a).