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irga5000 [103]
2 years ago
7

A glass bottle filled with oil weighs 590 grams. After Sophia uses 200 milliliters of oil, the bottle weighs 400 grams. The weig

ht M of the bottle of oil, in grams, is a function of V, the volume, in milliliters, of oil Sophia has used. Write the function’s formula. M=__
Mathematics
1 answer:
iris [78.8K]2 years ago
7 0

Answer:  The answer is M=590-\dfrac{19}{20}V.


Step-by-step explanation: Given that a glass bottle is filled with oil weighs 590 grams. After that, Sophia uses 200 millilitres of oil and then the bottle weighs 400 grams.

Therefore, the weight of the oil that Sophia uses = 590 - 400 = 190 grams.

That is, 190 grams = 200 millilitres, so

1~\textup{ ml}=\dfrac{190}{200}~\textup{grams},\\\\\textup{V ml}=\dfrac{19}{20}\textup{V}~\textup{grams}.

So, the relation between the weight 'M' of the bottle of oil, in grams, is a function of 'V', the volume of oil Sophia used is given by

\textup{M}=590-\dfrac{19}{20}\textup{V}.


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Step-by-step explanation:

(a) Marginal cost is defined as the decrease or increase in total production cost if output is increased by one more unit. Mathematically:

Marginal cost (MC) = change in total cost/change in quantity

Therefore, to derive the equation for total production cost, we need to integrate the equation of marginal cost with respect to quantity. Thus:

Total cost (C) = Integral [3(q-4)^2] dq = -(1/4)*(q-4)^3 + k

where k is a constant.

The overhead (OH) = C(0) = -(1/4)*(0-4)^3 + k = -16 + k

C(q) = -(1/4)*(q^3  - 12q^2  + 48q - 64) + k = -(1/4)*q^3 +  3q^2  -  12q  -16 + k

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C(q) =  -(1/4)*q^3 +  3q^2  -  12q + OH

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At a certain company, the annual winter party is always held on the second of Friday of December. What is the latest possible da
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2 years ago
A torch and a battery cost £2.50 altogether. The torch costs £2.00 more than the battery.
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Answer:

\frac{1}{10}

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Let t represent the cost of the torch and b represent the cost of the battery.

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We express this as a fraction of the total cost which is £2.50 to get;

\frac{0.25}{2.5}=\frac{1}{10}

8 0
2 years ago
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