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dangina [55]
2 years ago
15

Drag the tiles to the correct boxes to complete the pairs. Match the x-coordinates with their corresponding pairs of y-coordinat

es on the unit circle.
Mathematics
2 answers:
8090 [49]2 years ago
8 0

Answer:

(ON Plato)

Square root 5 over 3 = 2 over 3

Scare root 7 over 3 =Square root of 2 over 3

3 over 5 =4 over 5

2 the square root of 2 over 3 =1 over 3

Step-by-step explanation:


salantis [7]2 years ago
6 0

Answer:

Do you have the stuff for it?


You might be interested in
Trapezoid STUV with vertices S(-3,6),T(0,7),U(1,4),and V(-5,2): (x,y)>(x+7,y-9)​
hjlf

Answer:

See below

Step-by-step explanation:

<u>Given points:</u>

  • S(-3,6),T(0,7),U(1,4),and V(-5,2)

<u>Translation rule: </u>

  • (x,y) → (x+7,y-9)​

<u>New coordinates by applying the rule:</u>

  • S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)

See attached for the graph

The blue trapezoid is STUV and the red one is S'T'U'V'

7 0
2 years ago
among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
Marilyn has 10 caramels, 12 mints, and 14 bars of dark chocolate in a bag. She picks three items from the bag without replacemen
Gemiola [76]
10+12+14 = 36

12/36 x 11/35 x 14/34 = 11/255

There's your answer.
3 0
2 years ago
Read 2 more answers
Below are boxplots that summarize the weights (in pounds) of large samples from two breeds of dog: the Anatolian Shepherd and th
koban [17]

Answer:

(a) The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of both plots is also same that is 75 pounds.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively

(b) Any data point which is greater than 155 or smaller than 80 will be considered an outlier.

Step-by-step explanation:

A box plot is a graph which shows five statistical characteristics of a data set.

1. Maximum value

2. Minimum value

3. Median

4. Upper Interquartile

5. Lower interquartile

(a) Compare the distributions of weights for the two dog breeds

Please refer to the attached diagram of the question.

The median of both plots is same, 120 pounds is the median weight of Anatolian Shepherd and the Black Russian Terrier breed.

The range of Anatolian Shepherd is,

Range = Maximum value - Minimum value

Range = 175 - 100 = 75 pounds

The range of Black Russian Terrier is,

Range = Maximum value - Minimum value

Range = 155 - 80 = 75 pounds

Therefore, the range of both plots is also same that is 75 pounds.

A box-plot is considered to be normally distributed when the median is at the center of upper quartile and lower quartile.

The box plot of Anatolian Shepherd is skewed towards left therefore, it is considered to be positively distributed.

The box plot of Black Russian Terrier is skewed towards right therefore, it is considered to be negatively distributed.

(b) What weights would a Black Russian Terrier have to be to be considered an outlier?

An outlier is a data point in the data set that is very different from the other data points.

In this case, the maximum and minimum values in the Black Russian Terrier box-plot are

Maximum = 155

Minimum = 80

Therefore, any data point which is greater than 155 or smaller than 80 will be considered an outlier.

5 0
2 years ago
Helps pls HELPPPPPPP
Brrunno [24]

Answer: Third option.

Step-by-step explanation:

Let be "x" the approximate actual width  (in feet) of the car.

Based on the information provided in the exercise, you know that the scale of the model car is this one:

1:32

Which can be written as a fraction:

\frac{1}{32}

Therefore, if you know that the width of the model car is 2.3 inches, you can set up the following proportion:

\frac{1}{32}=\frac{2.3}{x}

Finally, you must solve for "x" in order to find its value.

So you get the following result:

(x)(\frac{1}{32})=2.3\\\\x=(2.3)(32)\\\\x=73.6

8 0
2 years ago
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