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marissa [1.9K]
2 years ago
8

10 POINTS AND WILL GIVE BRAINLIEST

Mathematics
1 answer:
madam [21]2 years ago
7 0

The final value of the car will be given by:

final = origamt(1 - .20) to the 4th power. The car will retain therefore,only 80% of its original value from the preceding year for each of the 4 years starting with an original value of $35000.

The calculation is

final \:  value \\  = (35000) {(.8)}^{4}  \\  = 35000 \times .4096 \\  =

A measely $14,336!

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Dominique paid $15.50 to join an online music service. If
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Answer:

94.7

Step-by-step explanation:

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What is 0.514 written as a power of 10? 514 x 102 514 x 103 514 x 10-3
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0\underbrace{.514}_{3\to}=514\cdot10^{-3}
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Lawrence has two part-time jobs one at the movie theater and wanted a pet store he's paid by the hour at each job last week he w
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Let x be the earnings/hour at the movie theater.
      y be the earnings/hour at the pet store

Systems of equations:

$152.50 = 10x + 8y
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2 years ago
Question Number 12 You are a landscaper working on the design of a parking lot in a new shopping center. You are measuring the l
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Answer:

Length\: of\: D=37\frac{3}{16}  \:feet

Step-by-step explanation:

The following are the given information:

  • The handicapped spot, which is 10\frac{1}{16} feet wide and next to the curb.
  • The other three spots are 8\frac{3}{8} feet wide.
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The Median D therefore will be a sum of the following:

  • The width of the Handicapped Spot
  • 3 X The width of the other spots
  • 4 X The width of the dividing line

= 10\frac{1}{16} + (3 X 8\frac{3}{8})+(4 X\frac{1}{2})\\=\frac{161}{16} +  \frac{3 X 67}{8}+\frac{4}{2}\\=\frac{161}{16} +  \frac{201}{8}+\frac{4}{2}\\=\frac{161+402+32}{16}\\=\frac{595}{16}\\Length\: of\: D=37\frac{3}{16}  \:feet

7 0
2 years ago
Find a set of scalar parametric equations for the line formed by the two intersecting planes. 3x+3y+2z+2=0 2x−3y+2z−2=0
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The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).

Using x=0, we can find a point on this line by solving the simultaneous equations that remain:

... 3y +2z = -2

... -3y +2z = 2

Adding these, we get

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so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...

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Then our parametric equations can be written as

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