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marissa [1.9K]
2 years ago
8

10 POINTS AND WILL GIVE BRAINLIEST

Mathematics
1 answer:
madam [21]2 years ago
7 0

The final value of the car will be given by:

final = origamt(1 - .20) to the 4th power. The car will retain therefore,only 80% of its original value from the preceding year for each of the 4 years starting with an original value of $35000.

The calculation is

final \:  value \\  = (35000) {(.8)}^{4}  \\  = 35000 \times .4096 \\  =

A measely $14,336!

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32.15 is written correctly in EXPANDED FORM using FRACTIONS
marshall27 [118]

Answer:

Step-by-step explanation:

: Read and write decimals to thousandths using base-ten numerals, number names, and expanded form, e.g., 347.392 = 3 × 100 + 4 × 10 + 7 × 1 + 3 × (1/10) + 9 × (1/100) + 2 × (1/1000).

5 0
2 years ago
Two new drugs are to be tested using a group of 60 laboratory mice, each tagged with a number for identification purposes. Drug
lakkis [162]

Answer:

4.979044478499338 × 10²⁶

Step-by-step explanation:

Combination can be used to determine the number of ways the mice can be selected for the drugs (A, B) and the control group.

Combination factorial is define by  ⁿCr = \frac{n!}{(n-r)!r!}

21 group of mice receiving Drug A  can be selected in ⁶⁰C₂₁ = \frac{60!}{21!39!}

(60 - 21 = 39 ) mice remained for selection of 21 mice for the second drug

Drug B 21 mice can be chosen with ³⁹C₂₁ = \frac{39!}{21!18!}

( 39 - 21 = 18)  remained for control with ¹⁸C₁₈ = \frac{18!}{18!0!}

The number of ways the mice can be chosen for drug A, drug B and the control = ⁶⁰C₂₁ × ³⁹C₂₁ × ¹⁸C₁₈ = \frac{60!}{21!39!} × \frac{39!}{21!18!} × \frac{18!}{18!0!} = 4.979044478499338 × 10²⁶

8 0
2 years ago
Triangle A B C is shown. Angle A C B is a right angle. The length of hypotenuse A B is 12 centimeters, the length of C B is 9.8
Paha777 [63]

Answer:

tan−1(StartFraction 6.9 Over 9.8 EndFraction)

Step-by-step explanation:

tan−1(StartFraction 6.9 Over 9.8 EndFraction)

tan = opp/adj = 9.8/6.9

tan -1 = 1 / tan = 1 / (9.8 /6.9) = 6.9 /9.8

4 0
2 years ago
Read 2 more answers
A fabric store sells two types of ribbon. One customer buys 3 rolls of the lace ribbon and 2 rolls of the satin ribbon and has a
stepan [7]
<span>Let L be the number of yards on a roll of lace ribbon. Let S be the number of yards on a roll of satin ribbon. We can set up two equations. equation 1: 3L + 2S = 120 yards equation 2: 2L + 4S = 160 yards We can multiply (equation 1) by 2 and subtract (equation 2). equation 1: 6L + 4S = 240 yards equation 2: 2L + 4S = 160 yards 4L = 80 yards L = 20 yards equation 1: 3L + 2S = 120 yards 3(20 yards) + 2S = 120 yards 2S = 60 yards S = 30 yards There are 20 yards on a roll of lace ribbon. There are 30 yards on a roll of satin ribbon.</span>
7 0
2 years ago
The line 3y+x=25 is a normal to the curve y=x2-5x+k.find the value of constant k.
ladessa [460]

Answer:

k = 11.

Step-by-step explanation:

y = x^2 - 5x + k

dy/dx = 2x - 5 = the slope of the tangent to the curve

The slope of the normal = -1/(2x - 5)

The line  3y + x =25 is normal to the curve so finding its slope:

3y = 25 - x

y = -1/3 x + 25/3 <------- Slope is -1/3

So at the point of intersection with the curve, if the line is normal to the curve:

-1/3 = -1 / (2x - 5)

2x - 5 = 3  giving x = 4.

Substituting for x in y = x^2 - 5x + k:

When x = 4, y =  (4)^2 - 5*4 + k  

y = 16 - 20 + k

so y = k - 4.

From the equation y = -1/3 x + 25/3,  at x = 4

y = (-1/3)*4 + 25/3 = 21/3 = 7.

So y = k - 4 = 7

k = 7 + 4 = 11.

6 0
2 years ago
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