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malfutka [58]
2 years ago
13

An object having a mass of 2.0 kilograms falls from a height of 15 meters. What is its kinetic energy when it hits the ground?

Physics
1 answer:
irakobra [83]2 years ago
4 0

The answer is 2.9 X 10 TO the 2 power.

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A red ball, initially at rest, is simultaneously hit by a blue ball traveling from west to east at 5 m/s and a green ball travel
andrezito [222]

Answer:

C. Between North and West

Explanation:

Since all have equal masses and the red ball and green ball are moving in south and east direction, the blue ball would most likely be moving between the north and West direction.

8 0
2 years ago
A uniform magnetic field makes an angle of 30o with the z axis. If the magnetic flux through a 1.0 m2 portion of the xy plane is
Irina18 [472]

Answer:

(b) 10 Wb

Explanation:

Given;

angle of inclination of magnetic field, θ = 30°

initial area of the plane, A₁ = 1 m²

initial magnetic flux through the plane, Φ₁ =  5.0 Wb

Magnetic flux is given as;

Φ = BACosθ

where;

B is the strength of magnetic field

A is the area of the plane

θ is the angle of inclination

Φ₁ = BA₁Cosθ

5 = B(1 x cos30)

B = 5/(cos30)

B = 5.7735 T

Now calculate the magnetic flux through a 2.0 m² portion of the same plane

Φ₂ = BA₂Cosθ

Φ₂ = 5.7735 x 2 x cos30

Φ₂ = 10 Wb

Therefore, the magnetic flux through a 2.0 m² portion of the same plane is is 10 Wb.

Option "b"

3 0
2 years ago
a marine biologist wants to know the total vertical distance a dolphin travel during a jump with the surface of the water being
marin [14]

From the starting depth to the surface, the vertical distance is 35 ft.

From the surface to the peak of the jump, the vertical distance is 27 ft.

From the peak of the jump to the surface, the vertical distance is 27 ft.

From the surface to the ending depth, the vertical distance is 18 ft.

Then the total vertical distance is ...

  35 ft + 27 ft + 27 ft + 18 ft = 107 ft

3 0
2 years ago
Read 2 more answers
From Gauss's law, the electric field set up by a uniform line of charge is given by the following expression where is a unit vec
Evgesh-ka [11]

Answer:

\Delta V=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

Explanation:

Using the Gauss Law, we obtain the electric Field for a uniform large line of charge:

2\pi r L*E=\lambda *L/\epsilon_{o}

E=\lambda /\(2 \pi* r *\epsilon_{o})

We calculate the potential difference from the electric field:

\Delta V=-\int\limits^{r_{1}}_{r_{2}} E \, dr =-\int\limits^{r_{1}}_{r_{2}} \lambda dr/ (2\pi*r*\epsilon_{o})=\lambda *ln(r_{2}/r_{1}) /\ (2\pi*\epsilon_{o})

5 0
2 years ago
A heavy boy and a lightweight girl are balanced on a massless seesaw. If they both move forward so that they are one-half their
Yuki888 [10]

Answer:

The system is still balanced

Explanation:

If we suppose that the boy weights M and the girl m, and are balanced at distances L1 and L2 from the pivot point respectively, thy will be balanced if the resultant torque of all the farces from the pivot pint is cero:

(1)T=M*L1-m*L2=0

now they moved to distances (L1)/2 and (L2)/2, the resultant torque will be:

(2)T=M*(L1)/2-m*(L2)/2

1/2 can be taken out as a common factor:

(3)T=(M*L1-m*L2)*1/2

As the the inside of the parenthesis equals equation (1) that equals zero, hte whole equiation equals zero:

(3)T=(0)*1/2=0

So the system is still balanced

6 0
2 years ago
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