Answer:
the probability the rock has raritanium is 0.9670
Step-by-step explanation:
These events have been defined as
Z: sample has raritanium
Y: the reading from detector is positive
Z': sample has no raritanium
Y': Reading from detector is negative
P(z) = 0.13
P(y'/z) = 0.02
P(y/z')= 0.005
We need to find p(z/y)
= p(z/y) = p(z ∩ y)/p(y)
= P(z) - p(z∩y)/0.13 = 0.02
Remember the value of p(z) = 0.13
So when we cross multiply we get
0.13 - p(z ∩ y) = 0.02 x 0.13
0.13 - p(z ∩ y) = 0.0026
-p(z ∩ y) = 0.0026 - 0.13
Such that
p(z ∩ y) = 0.1274
P(y/z')= 0.005
P(z∩y') = 0.005
Since p(z) = 0.13
P(z') = 1-0.13
P(y) - p(z∩y)/0.87 = 0.005
We cross multiply
P(y) - 0.1274 = 0.005x0.87
P(y) = 0.1274+0.00435
P(y) = 0.13175
We have 0.1274/0.13175
= 0.9670
So we conclude that probability rock has raritanium is 0.9670
Answer:
Step-by-step explanation:
From the information given,
Number of sample, n = 200
Probability of success, p = 43/100 = 0.43
q = 1 - p = 1 - 0.43
q = 0.57
For a confidence level of 95%, the corresponding z value is 1.96.
The formula for determining the error bound for the proportion is
z × √pq/n
= 1.96 ×√(0.43 × 0.57)/200
= 1.96 × 0.035 = 0.0686
The upper boundary of the population proportion is
0.43 + 0.0686 = 0.5
The lower boundary of the population proportion is
0.43 - 0.0686 = 0.4
The error in the solution is
phat = 0.43/200 = 0.00215
Also,
[-0.0043, 0.0086] is wrong
Answer: Third option is correct.
Step-by-step explanation:
Since we have given that
Mean = 10
Sample size = 9
Standard deviation = 6
We need to find the upper and lower control limits.
so, Lower limit would be

Upper limit would be

Hence, Third option is correct.
Answer:
The last two terms of the expression are

Both the last terms has variable of degree equal to (2+4=6) and (3+3=6).So, the first term must have degree greater than 6.
Correct Options are
