All categories

2 years ago

You apply a force of 18 N on to the end of a lever to open a paint can lid. The resistance of the lid is 9 N. Calculate the MA.

Physics

2 answers:

Lana71 [14]2 years ago

7 0

Answer:

MA = 0.5

Explanation:

MA = (Useful Force) / (Input Force)

MA = (18 - 9) N / 18 N = 9 / 18

Hence, MA = 0.5

Answer: MA = 0.5

krek1111 [17]2 years ago

6 0

Answer:

MA = 0.5

Explanation:

The mechanical advantage is defined as:

MA = Resistance_force / Effort_force

Resistance_force = 9 N

Effort_force = 18 N

We substitute,

MA = 9N / 18 N

MA = 0.5

You might be interested in

An object at rest is suddenly broken apart into two fragments by an explosion one fragment acquires twice the kinetic energy of

satela [25.4K]

First, we use the kinetic energy equation to create a formula: Ka = 2Kb 1/2(ma*Va^2) = 2(1/2(mb*Vb^2)) The 1/2 of the right gets cancelled by the 2 left of the bracket so: 1/2(ma*Va^2) = mb*Vb^2 (1) By the definiton of momentum we can say: ma*Va = mb*Vb And with some algebra: Vb = (ma*Va)/mb (2) Substituting (2) into (1), we have: 1/2(ma*Va^2) = mb*((ma*Va)/mb)^2 Then: 1/2(ma*Va^2) = mb*(ma^2*Va^2)/mb^2 We cancel the Va^2 in both sides and cancel the mb at the numerator, leving the denominator of the right side with exponent 1: 1/2(ma) = (ma^2)/mb Cancel the ma of the left, leaving the right one with exponent 1: 1/2 = ma/mb And finally we have that: mb/2 = ma mb = 2ma

8 0

2 years ago

Rod A has twice the diameter of rod B, but both are made of iron and have the same initial length. Both rods are now subjected t

Vilka [71]

Answer:

ΔLa/ΔLb = 1

Explanation:

The change in length of a solid is given by the following formula:

ΔL = α L ΔT

where,

ΔL = Change in length

α = coefficient of linear expansion

L = Original Length

ΔT = Change in Temperature

Since, the length and change in temperature for both rods are same. Also, the material of each rod is same, which implies that coefficient of linear expansion for both rods is same. Hence, the ratio of change in length of both rods will be:

ΔLa/ΔLb = 1

4 0

2 years ago

A child tugs on a rope attached to a 0.62-kg toy with a horizontal force

Katarina [22]

Answer:

$a=0.8\ m/s^2$

Explanation:

Given that,

Mass of a toy, m = 0.62 kg

Horizontal force, F = 16.3 N

Force on the opposite direction, F' = 15.8 N

We need to find the acceleration of the toy.

Here, two forces are acting in opposite direction, the net force will be the difference of forces.

Net force = 16.3 N-15.8 N

=0.5 N

The formula for net force is given by :

F = ma

a is the acceleration of the toy

$a=\dfrac{F}{m}\\\\a=\dfrac{0.5\ N}{0.62\ kg}\\\\a=0.8\ m/s^2$

So, the acceleration of the toy is $0.8\ m/s^2$ .

6 0

2 years ago

A bullet blasts from the barrel of a gun upward in the vertical direction with an initial speed of 700 m/s . Find the maximum al

ryzh [129]

The maximum altitude that the bullet will reach is the point at which its velocity is zero. The equation that may be used in order to determine the altitude is,

D = ((Vi)2 – (Vf)2)/2g

Where Vi and Vf are the initial and final velocities, respectively. g is the deceleration due to gravity.

Substituting the known values,

D = ((700 m/s)2 – (0 m/s)2) / (2(-9.8 m/s2))

D = 25000 m

Thus, the maximum height is 25000 m.

For the time needed to reach it, we use the equation,

Vf = Vi – (g)(t)

Substituting,

0 = 700 m/s – (-9.8 m/s2)(t)

The value of t is equal to 71.43 s.

6 0

2 years ago

What is the mass of an object weighing 63 N on Earth?

avanturin [10]

Weight expressed in Newtons is expressed in the equation whereby Weight= the mass of an object * the force of gravity. The force of gravity on earth is a constant 9.8 meters per second squared. Therefore if weight (w) = 63 N and the force of gravity is 63 N then the mass must equal 6.43 kg. Because the equation for weight is w=mg so 63 N (w) = m * 9.8 m/s^2.

3 0

2 years ago