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Alexandra [31]
2 years ago
11

A force of 19 newtons is applied on a cart of 2 kilograms, and it experiences a frictional force of 1.7 newtons. What is the acc

eleration of the cart? A. 8.6 meters/second2 B. 9.0 meters/second2 C. 9.5 meters/second2 D. 10.5 meters/second2 E. 0.8 meters/second2
Mathematics
2 answers:
Snezhnost [94]2 years ago
6 0

Answer:

letter a

Step-by-step explanation:

arsen [322]2 years ago
4 0

Answer:

option A

a = 8.65 m/s²

Step-by-step explanation:

Given that,

force applied on a cart (forward direction) = 19N

frictional force experience by cart (backward direction) = 1.7N

mass of the cart = 2 kg

Frictional force always opposes applied force, so the Resultant force on the cart would have to be 19N - 1.7N.

Formula to use

Resultant force = ma

plug values in the formula

19 - 1.7 = 2(a)

17.3 = 2(a)

a = 8.65 m/s²

so the acceleration of the cart is 8.65m/s²

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Let x represent time taken by 20 members to paint 9000 square foot wall.

We have been given that all members of our painting team paint at the same rate. 20 members can paint a 6000 square foot wall in 24 minutes. We are asked to find the time taken by 20 members to paint 9000 square foot wall.

We will use proportions to solve our given problem.

\frac{\text{Time taken}}{\text{Area of wall painted}}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}=\frac{24\text{ min}}{6000\text{ ft}^2}

\frac{x}{9000\text{ ft}^2}\times 9000\text{ ft}^2=\frac{24\text{ min}}{6000\text{ ft}^2}\times 9000\text{ ft}^2

x=\frac{24\text{ min}}{6}\times 9

x=4\text{ min}\times 9

x=36\text{ min}

Therefore, it will take 36 minutes for 20 members to paint 9000 square foot wall.

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1 year ago
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Minchanka [31]

Answer:

  • Benito's error was using the equal sign (=) instead of the congruency symbol (≅).

Explanation:

Benito's error was using the equal sign (=) instead of the congruency symbol (≅).

The congruency symbol (≅) means that the elements (segments, angles or figures in general) have the same measure, i.e. they have equal lengths for the segments or equal measure for the angles.

For instance, it is an error saying that the segment AB is equal to the segment BC because, as you clearly see in the picture, they are not same; they have the same length but they are joining different points, that makes them different in essence, although they have the same length. They would be equal only if they are the same figure.

In mathematics, you must not say that two different segments or two different angles are equal but they are congruent, which means that their lengths are equal. The use of equal is reserved for numbers and variables, not for figures like segment, points, angles, polygons.

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Under what circumstances will the chi-square test for goodness of fit produce a large value for chi-square? Question options: a.
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Answer:

a.when the sample proportions are much different than the hypothesized population proportions

Step-by-step explanation:

A chi-square test for goodness of fit is used to check the sample data were distributed according to claim or not.

If the chi-square test produces a large value of chi-square statistic then there is not a good fit between sample data and the null hypothesis. So, the sample proportions are much different than the hypothesized population proportions. Hence,Option (a) is correct.

If the goodness of fit produces a large value for chi-square then the sample means must not be close to the population mean. So, option (b) is incorrect.

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Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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ANTONII [103]
Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations.
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