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2 years ago

Hannah was asked to make d the subject of the formula

Mathematics

1 answer:

labwork [276]2 years ago

8 0

Answer:

Step-by-step explanation:

Multiply both sides of the equation by e

d*e - 7*e = 4d + 3

de - 7e goes into the first box on top.

==================

The second box is obtained in two steps.

Step One

Add 7e to both sides.

de - 7e + 7e = 4d + 3 + 7e

de = 4d + 3 + 7e

Step Two

Subtract 4d from both sides.

de - 4d = 4d - 4d + 3 + 7e

de - 4d = 3 + 7e

de - 4d goes into the middle box.

================================

Take out d as a common factor

d(e - 4) = 3 + 7e

d(e - 4) goes into the third box from the top.

=============================

Divide both sides by e - 4

3 + 7e

d = ---------

e - 4

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2 years ago

Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your methods as well

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Answer:

The value is $P(A) = 0.133617$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 7.5$

The standard deviation is $\sigma = 0.2$

The safest water level is between 7.2 and 7.8

Generally the probability that the selected pool has a pH level that is not considered safe is mathematically represented as

$P(A) = 1 - P(7.2 \le X \le 7.8 )$

Here

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - \mu }{\sigma } < \frac{X - \mu }{ \sigma }$

Generally $\frac{X - \mu }{ \sigma } = Z (The \ standardized \ value \ of X )$

$P(7.2 < X < 7.8 ) = P(\frac{ 7.2 - 7.5 }{0.2 } < Z$

$P(7.2 < X < 7.8 ) = P(-1.5 < Z$

=> $P(7.2 < X < 7.8 ) = P(Z < 1.5) - P( Z < - 1.5)$

From the z-table the probability of (Z < -1.5) and ( Z <1.5) are

$P(Z < 1.5) = 0.93319$

and

$P(Z < -1.5) = 0.066807$

$P(7.2 < X < 7.8 ) =0.93319 - 0.066807$

$P(7.2 < X < 7.8 ) =0.0866383$

$P(A) = 1 - 0.0866383$

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1 year ago

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Answer:

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Step-by-step explanation:

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2 years ago

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For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

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Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

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2 years ago

Lonzell said the function shown in the graph is positive on the interval (−,) and negative on the interval (−,−)open negative 5

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Answer:

The positive graph is on the points (-5,-4) and (2,5)

And, negative would be (-4,2)

Step-by-step explanation:

As it seems that fgraph shows positive in the case when it is over x-axis, and negative when it is below y-axis

As on the interval (-1,5)

The graph is below x-axis i.e. on (-1,2)

And, over x-axis i.e. on (2,5)

At this point Lonzell’s is not correct

As on the interval (-5,-1)

The graph is below x-axis i.e. on (-4,-1)

And, over x-axis i.e. on (-5,4)

At this point Lonzell’s is not correct

So,

The positive graph is on the points (-5,-4) and (2,5)

And, negative would be (-4,2)

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2 years ago