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marishachu [46]
2 years ago
5

Kyle volunteered 5.5 hours at the library this week. He needs to volunteer a total of 12 hours. Which equation can be used to fi

nd the number of hours, h, Kyle still needs to volunteer this week?
Mathematics
2 answers:
bonufazy [111]2 years ago
5 0

Answer:

12-5.5=h

12-5.5=6.5

Kyle needs to volunteer 6.5 more hours.

Step-by-step explanation:

Citrus2011 [14]2 years ago
4 0

Answer:

5.5 + h = 12

Step-by-step explanation:

Here, h represents the number of hours, Kyle still needs to volunteer this week,

Given,

He volunteered 5.5 hours at the library this week.

Since, the total number of hours he needs to volunteer = 5.5 + h

According to the question,

5.5 + h = 12

Which is the required equation.

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Two well-known aviation training schools are being compared using random samples of their graduates. It is found that 70 of 140
egoroff_w [7]

Answer:

Step-by-step explanation:

Given that two well-known aviation training schools are being compared using random samples of their graduates

Fly more academy 70 of 140

Blue Yonder   104 of 260

Combined pass = (70+104) out of (140+260)

a) Pooled proportion=\frac{174}{400} \\=0.435

b) H0: p1 = p2

Ha: p1 ≠p2

(two tailed test)

p difference= \frac{70}{140} -\frac{104}{260} =0.10

std error for difference (using pooled proportion) = \sqrt{\frac{0.435*0.565}{400} } \\=0.0248

Test statistic = p difff/std error = 4.034

c) Critical value for 0.05 is 1.96

d) p value is < 0.005

Since p < 0.05 our significant level we reject H0

There is significant difference between the two proportions.

8 0
2 years ago
A study is being conducted in which the health of two independent groups of ten policyholders is being monitored over a one-year
uysha [10]

Answer:

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

Step-by-step explanation:

We use two binomial trials to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least nine participants finishing the study in a group.

0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that p = 0.8.

10 students, so n = 10

We have to find:

P(X \geq 9) = P(X = 9) + P(X = 10)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.8)^{9}.(0.2)^{1} = 0.2684

P(X = 10) = C_{10,10}.(0.8)^{10}.(0.2)^{0} = 0.1074

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2684 + 0.1074 = 0.3758

0.3758 probability that at least nine participants complete the study in a group.

Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?

0.3758 probability that at least nine participants complete the study in a group. This means that p = 0.3758

Two groups, so n = 2

We have to find P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.3758)^{1}.(0.6242)^{1} = 0.4691

46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups

5 0
2 years ago
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Step-by-step explanation:

an² = 182

When a = 2, n² = 182/2 = 91, n = 9.539...

When a = 5, n² = 182/5 = 36.4, n = 6.033...

Since 2 <= a <= 5, we have 6.033 <= n <= 9.539.

Therefore our possible values of n are 7, 8 and 9.

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Megan and Sam were solving a system of equations. They both noticed that the two lines had different slopes. Megan said that bec
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Your answer is A. Megan is correct. When two lines have different slopes, they must intersect, producing one solution.

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