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patriot [66]
2 years ago
3

How much chlorine should be produced if 84.2 grams of aluminum chloride and 68.4 grams bromine are combined? 2AlCl3 + 3Br2 —>

3AlBr3 + 2Cl2
Chemistry
1 answer:
mote1985 [20]2 years ago
7 0

Answer:

20.27 g.

Explanation:

  • From the balanced reaction:

<em>2AlCl₃ + 3Br₂ → 3AlBr₃ + 2Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 moles of Br₂ to produce 3.0 mole of AlBr₃, and 2.0 mole of Cl₂.

  • We need to calculate the no. of moles of (84.2 g) of AlCl₃ and (68.4 g) of Br₂:

no. of moles of AlCl₃ = mass/molar mass = (84.2 g)/(133.34 g/mol) = 0.6315 mol.

no. of moles of Br₂ = mass/molar mass = (68.4 g)/(159.808 g/mol) = 0.4288 mol.

AlCl₃ reacts with Br₂ with (2: 3) molar ratio,

<em>So, 0.2859 mole (the remaining is in excess) reacts completely with 0.4288 mole of Br₂.</em>

<em />

<u><em>Using cross multiplication:</em></u>

2.0 moles of AlCl₃ produce → 2.0 moles of Cl₂.

∴ 0.2859 mole of AlCl₃ produce → 0.2859 mole of Cl₂.

<em>∴ The amount of Cl₂ produced = no. of moles x molar mass </em>= (0.2859 mol)(70.906 g/mol) = <em>20.27 g.</em>

<em />

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Answer : The number of bonding electrons and the number of non-bonding electrons are (4, 18).

Explanation :

The number of bonding electrons and non-bonding electrons in the structure of XeF_2 is determined by the Lewis-dot structure.

Lewis-dot structure : It tell us about the number of valence electrons of an atom within a molecule and it is also shows the bonding between the atoms of a molecule and the lone-pair of electrons.

In the given structure, 'Xe' is the central atom and 'F' is the terminal atom.

Xenon has 8 valence electrons and fluorine has 7 valence electrons.

Total number of valence electrons in XeF_2 = 8 + 2(7) = 22 electrons

From the Lewis-dot structure, we conclude that

The number of electrons used in bonding = 4

The number of electrons used in non-bonding (lone-pairs) = 22 - 4 = 18

Therefore, the number of bonding electrons and the number of non-bonding electrons are (4, 18).

The Lewis-dot structure of XeF_2 is shown below.

4 0
2 years ago
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1. Which liquid sample is a pure substance?
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The whole Activity , poem and paragraph is missing in the question.

Answer:

(1) Liquid A

(2) Solid A

Explanation:

Using this part of the given poem

Substances and mixtures behave differently,

During boiling and melting most especially

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Answer:

11482 ppt of Li

Explanation:

The lithium is extracted by precipitation with B(C₆H₄)₄. That means moles of Lithium = Moles B(C₆H₄)₄. Now, 1 mole of B(C₆H₄)₄ produce the liberation of 4 moles of EDTA. The reaction of EDTA with Mg²⁺ is 1:1. Thus, mass of lithium ion is:

<em>Moles Mg²⁺:</em>

0.02964L * (0.05581mol / L) = 0.00165 moles Mg²⁺ = moles EDTA

<em>Moles B(C₆H₄)₄ = Moles Lithium:</em>

0.00165 moles EDTA * (1mol B(C₆H₄)₄ / 4mol EDTA) = 4.1355x10⁻⁴ mol B(C₆H₄)₄ = Moles Lithium

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4.1355x10⁻⁴ moles Lithium * (6.941g/mol) = 0.00287g. In μg:

0.00287g * (1000000μg / g) = 2870μg of Li

As ppt is μg of solute / Liter of solution, ppt of the solution is:

2870μg of Li / 0.250L =

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