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Bogdan [553]
1 year ago
5

A sealed, insulated calorimeter contains water at 310 K. The surrounding air temperature is 298 K, and the water inside the calo

rimeter remains at 310 K two hours later. What type of system does the calorimeter attempt to model?
A closed system, because energy can enter or leave the system, but matter cannot.


A closed system, because neither heat nor matter is entering or leaving the container.


An isolated system, because energy can enter or leave the system, but matter cannot.


An isolated system, because neither heat nor matter is entering or leaving the container.
Chemistry
2 answers:
tatiyna1 year ago
8 0

Answer:

An isolated system, because neither heat nor matter is entering or leaving the container.

Explanation:

In a closed system there is no exchange of heat but matter is exchanged. In an isolated system there is no exchange of heat or matter. Here the temperature of water remains constant at 310 K, which means that no heat is exchanged. Also there is no decreases in volume of water the calorimeter after 2 hours, which means that no matter was lost either. Therefore this is an isolated system.

serious [3.7K]1 year ago
7 0
D is the answer, I believe.

An isolated system is one that allows neither heat or matter to enter or exit, and since the liquid remained the same temperature, one can conclude that neither energy nor matter is passing through.
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The successive ionization energies of a certain element are I1 = 589.5 kJ/mol, I2 =1145 kJ/mol, I3= 4900 kJ/mol, I4 = 6500 kJ/mo
Gnom [1K]

Answer:

As

Explanation:

For any element to exhibit the pattern of ionization energy shown in the question, it must possess five electrons in its outermost shell. These five electrons are not lost at once. They are lost progressively until the valence shell becomes empty. The ionization energy increases steadily as more electrons are lost from the valence shell.

The only pentavalent element among the options in arsenic, hence the answer.

7 0
2 years ago
Read 2 more answers
Glade air freshener gel “disappearing” is an example of
netineya [11]

Answer:

Vaporization

Explanation:

Vaporization is the change of a specie to the gaseous state. To 'disappear' in this case simply means to change to the gaseous state.

Substances with high vapour pressure tend to be easily converted to vapour phase. Hence if Glade air freshener gel 'disappears' easily, then it has a high vapour pressure and is easily converted to vapour (gas).

8 0
1 year ago
A 0.1153-gram sample of a pure hydrocarbon was burned in a C-H combustion train to produce 0.3986 gram of CO2and 0.0578 gram of
Mars2501 [29]

<u>Answer:</u> The mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

C_xH_y+O_2\rightarrow CO_2+H_2O

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of CO_2=0.3986g

Mass of H_2O=0.0578g

Mass of sample = 0.1153 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 0.3986 g of carbon dioxide, \frac{12}{44}\times 0.3986=0.1087g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18g of water, 2 g of hydrogen is contained.

So, in 0.0578 g of water, \frac{2}{18}\times 0.0578=0.0066g of hydrogen will be contained.

To calculate the percentage composition of a substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of sample}}\times 100      ......(1)

  • <u>For Carbon:</u>

Mass of sample = 0.1153 g

Mass of carbon = 0.1087 g

Putting values in equation 1, we get:

\%\text{ composition of carbon}=\frac{0.1087g}{0.1153g}\times 100=94.27\%

  • <u>For Hydrogen:</u>

Mass of sample = 0.1153 g

Mass of hydrogen = 0.0066 g

Putting values in equation 1, we get:

\%\text{ composition of hydrogen}=\frac{0.0066g}{0.1153g}\times 100=5.72\%

Hence, the mass of carbon and hydrogen in the sample is 0.1087 g and 0.0066 g respectively and the percentage composition of carbon and hydrogen in the sample is 94.27 % and 5.72 % respectively.

8 0
1 year ago
How many moles of O2 would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 73.3% yi
Airida [17]

Answer:

Mmmmmmmmmmmmmmm

Explanation:

4 0
1 year ago
According to the quantum-mechanical model for the hydrogen atom, which electron transition produces light with the longer wavele
LekaFEV [45]

Answer:

Explanation:

The main task here is that there are some missing gaps in the above question that needs to be filled with the appropriate answers. So, we are just going to do rewrite the answer below as we indicate the missing gaps by underlining them and making them in bold format.

SO; In the quantum-mechanical model of the hydrogen atom.

As the n level increases. the energy <u>increases</u> and thus levels are <u>closer to </u>each other. Therefore, the transition <u>3p→2s</u> would have a greater energy difference than the transition from <u>4p→3p.</u>

Energy \  and \  wavelength  \ are \  inversely \   proportional , \  so \  the \ \mathbf{ 4p\to 3p} \ transition  \ wouldproduce  \ a  \ longer \ wavelength.

3 0
1 year ago
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