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ratelena [41]
2 years ago
12

What is the percent composition of silicon in silicon carbide (SiC)? A. 28% B. 50% C. 70% D. 142%

Chemistry
2 answers:
MAXImum [283]2 years ago
8 0

Hey there!

Here goes your answer ↓

Question :- What is the percent composition of silicon in silicon carbide (SiC)?

A. 28%

B. 50%

C. 70%

D. 142%

Answer :- <em>T</em><em>h</em><em>e</em><em> </em><em>percen</em><em>tage</em><em> </em><em>of</em><em> </em><em>silicon </em><em>content </em><em>in </em><em>silicon </em><em>carbide </em><em>(</em><em>SiC</em><em>)</em><em> </em><em>is</em><em> </em><em>option</em><em> </em><em>(</em><em>C</em><em>)</em><em> </em><em>7</em><em>0</em><em>%</em><em>.</em>

Hope it helps you.

Have a great day ahead!

PSYCHO15rus [73]2 years ago
4 0

Answer : The correct option is, (C) 70%

Explanation : Given,

Molar mass of Si = 28.09 g/mole

Molar mass of C = 12 g/mole

Molecular mass of SiC = 28.09 + 12 = 40.09 g/mole

To calculate the mass percent of an element in a compound, we use the equation:

\text{Percent composition of Si}=\frac{\text{Mass of Si in compound}}{\text{Mass of the compound}}\times 100

Now put all the given values in above equation, we get:

\text{Percent composition of Si}=\frac{28.09g}{40.09g}\times 100=70\%

Hence, the percentage composition of Si in the given compound is 70%

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A sample of 508.4 grams of copper completely reacted with oxygen to form 572.4 grams of a copper oxide product. how many grams o
Svet_ta [14]

According to law of conservation of mass, mass can neither be destroyed nor created in a chemical reaction. Thus, sum of masses of reactants must be equal to sum of masses of products in a reaction.

The chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, sum of masses of Cu and oxygen gas should be equal to CuO formed.

2m_{Cu}+m_{O_{2}}=2m_{CuO}

Thus, mass of oxygen will be:

m_{O_{2}}=2(572.4-508.4)g=128 g

This can be further proved as follows:

The balanced chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, 2 moles of Cu completely reacts with 1 mole of O_{2} to give 2 moles of CuO.

Thus, 1 mole of Cu reacts with 0.5 moles of O_{2} .

The mass of Cu is 508.4 and molar mass is 63.546 g/mol, number of moles can be calculated as follows:

n=\frac{m}{M}=\frac{508.4 g}{63.546 g/mol}=8 mol

Thus, number of moles of  O_{2} reacting will be:

n_{O_{2}}=8\times 0.5 mol=4 mol

Molar mass of oxygen molecule is 32 g/mol thus, mass can be calculated as follows:

m=n×M=4 mol×32 g/mol=128 g/mol

This satisfies the law of conservation of mass.


7 0
2 years ago
The nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calorie
Olenka [21]

Answer:

C. 100

Explanation:

Biochemical researches and studies have found out that an average health hotdog has a calorie of between 100 and 150 which is usually dependent on the additives.

Since the nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calories then it truly contains such amount of calories. The standard number of calories present in a hotdog is independent of the amount eaten by individuals.

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You have four water samples at different temperatures. In which sample are the molecules vibrating at the fastest speed? A. wate
tatiyna

Answer:

99°C

Explanation:

asking questions is Best in life of education

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2 years ago
Suppose total world energy consumption of fossil fuels, equal to 3×1017 kJ/yr, were to be obtained entirely by combustion of pet
Natasha_Volkova [10]

Answer:

it would definitely be wienerballs1977

Explanation:

fossil fuels x (3x1017kJ/yr) equals out to be wienerballs1977.

thx for the challenge !

3 0
2 years ago
Imagine that a new polyatomic anion called "platoate" is invented. What would an acid of "platoate" be named?
o-na [289]
<h3>Answer:</h3>

                   Platoic Acid

<h3>Explanation:</h3>

                        While naming Carboxylic Acids we know that when the Carboxylic Acid looses proton it is converted into corresponding conjugate base called as Carboxylate.

Examples:

                        HCOOH           →           HCOO⁻  +  H⁺

                     Formic acid                     Formate Ion

                    H₃CCOOH           →           H₃CCOO⁻  +  H⁺

                     Acetic acid                       Acetate Ion

                    H₅C₂COOH           →           H₅C₂COO⁻  +  H⁺

                 Propanoic acid                       Propanoate Ion

Therefore, if the conjugate base is Platoate then the corresponding acid will be Platoic Acid means we will replace the -ate by -ic acid <em>i.e.</em>

                   RCOO⁻  +  H⁺        →            RCOOH

                   Platoate Ion                         Platoic Acid

8 0
2 years ago
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