Answer:
VP as function of time => VP(Ar) > VP(Ne) > VP(He).
Explanation:
Effusion rate of the lighter particles will be higher than the heavier particles. That is, the lighter particles will leave the container faster than the heavier particles. Over time, the vapor pressure of the greater number of heavier particles will be higher than the vapor pressure of the lighter particles.
=> VP as function of time => VP(Ar) > VP(Ne) > VP(He).
Review Graham's Law => Effusion Rate ∝ 1/√formula mass.
Answer:
MnO- Manganese Oxide
Explanation:
Empirical formula: This is the formula that shows the ratio of elements
present in a
compound.
How to determine Empirical formula
1. First arrange the symbols of the elements present in the compound
alphabetically to determine the real empirical formula. Although, there
are exceptions to this rule, E.g H2So4
2. Divide the percentage composition by the mass number.
3. Then divide through by the smallest number.
4. The resulting answer is the ratio attached to the elements present in
a compound.
Mn O
% composition 72.1 27.9
Divide by mass number 54.94 16
1.31 1.74
Divide by the smallest number 1.31 1.31
1 1.3
The resulting ratio is 1:1
Hence the Empirical formula is MnO, Manganese oxide
Answer: Aluminum, 
Explanation:
Density is defined as the mass contained per unit volume. It is characteristic of a substance.
Given : Mass of object = 8.44 grams
Volume of object=
Putting in the values we get:
Thus density of the object will be
which matches that of aluminium.
Assume 100 g of compound. This turns percent to mass. Calculate moles:
S ---> 30/32 = 0.9375
F ---> 70 / 19 = 3.6842
get whole number ratio:
0.9375 / 0.9375 = 1
3.6842 / 0.9375 = 3.93 = 4
Answer : SF4
V = nRT / P = (4.53 mol) x (0.08205746 L atm/K mol) x (301 K) / (1.78 atm) = 62.9 L