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Ymorist [56]
2 years ago
6

A lab technician needs to create 570.0 milliliters of a 2.00 M solution of magnesium chloride (MgCl2). To make this solution, ho

w many grams of magnesium chloride does the technician need?
Refer to the periodic table for help. Express your answer to three significant figures.
Chemistry
1 answer:
love history [14]2 years ago
7 0

Answer:

108.3g

Explanation:

Given parameters:

Volume of solution = 570mm = 0.57L (1000mm = 1L)

Molarity of solution = 2M

Unknown

Mass of MgCl₂

Solution

We first find the  number of moles in the given concentration of magnessium chloride using the expression below:

       Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles

Using this known moles, we can the unknown mass of MgCl₂ the technician would require:

       Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass

Molar mass of MgCl₂:

Atomic mass of Cl = 35.5g

Atomic mass of Mg = 24g

MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹

Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g

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A converging lens with a focal length of 70.0cm forms an image of a 3.20-cm-tall real object that is to the left of the lens. Th
Setler [38]

Answer: (i)The object is at a distance of 120cm from the lens while the image is at a distance of 160cm from the lens. (ii)The image is Real

Note: This is the complete question; A converging lens with a focal length of 70.0cm forms an image of a 3.20-cm-tall real object that is to the left of the lens. The image is 4.50cm tall and inverted. Where are the object and image located in relation to the lens? Is the image real or virtual?

Explanation:

The required formulas are;

1. lens formula given by,  <em>1/s' + 1/s = 1/f</em>

2. magnification = <em>h'/h = s'/s</em>

where h' is image height, h is object height, s' is image distance, s is object distance, f is focal length of lens.

h' = 4.50cm, h = 3.20cm, f = 70cm ( f of a converging lens is positive)

solving for s' and s in eqn (2)

4.50/3.20=s'/s

1.4=s'/s

s'=1.4s

to find the values of s' and s, we use equation (1) and substitute s' = 1.4s

1/1.4s + 1/s = 1/70

2.4/1.4s =1/70

s = 2.4*70/1.4 = 120cm

s' = 1.4*120 = 160cm

Therefore, the object is on the left, 120cm from the lens while the image is 160cm on the right of the lens

<em>Since the object is at a distance between f and 2f from the lens, the image formed is</em> real, inverted and magnified

3 0
2 years ago
An alkene with the molecular formula C8H16 undergoes ozonolysis to yield a mixture of (CH3)2C=O and (CH3)3CCHO. The alkene is:
aalyn [17]

Answer:

2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Explanation:

In ozonolysis (hydrolysis step involve a reducing agent such as Zn, Me_{2}S etc.), a pi bond is broken to form ketone/aldehyde.

Ketone is formed from di-substituted side of double bond and aldehyde is formed from mono-substituted side of double bond.

Ozoznolysis involves two consecutive steps : (1) formation of ozonide, (2) hydrolysis of ozonide.

Hydrolysis can be done with/without using reducing agent. Carboxylic acid/carbon dioxide/ketone is produced when hydrolysis is done without using reducing agent.

Here, 2,4,4-trimethyl-2-pentene yields mixture of (CH_{3})_{2}C=O and (CH_{3})_{3}CHO

Reaction steps are shown below.

8 0
2 years ago
Write a hypothesis for this: Hummingbirds are attracted to the color red
Margaret [11]

Answer: I believe/don't believe hummingbirds are attracted to the color red because ... (Enter your reasons)

Explanation:

Hypothesis are always different, up to you to choose believe or not believe depending on your position.

:) Hope this helped.

8 0
2 years ago
The reaction of 0.779 g K with O2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. Dete
zhannawk [14.2K]
First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
  = 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
               = 0.02 mol 
the number of both K and O₂ moles reacted are equal 
therefore stoichiometry of K to O₂ reacted are 1:1 
then the formula of potassium superoxide is KO₂
3 0
2 years ago
A chemical engineer must report the average volume of a certain pollutant produced by the plants under her supervision. Here are
AfilCa [17]

Answer:

The chemical engineer should report average volume of 15.34 L.

Explanation:

Volume of Macon = 0.519 L

Volume of Allegheny = 44.67 L

Volume of Doheny = 0.826 L

Average of the volume of the pollutants:

\frac{0.519 L+44.67 L+ 0.826L}{3}=\frac{46.015 L}{3}=15.33833 L

The rule apply for the addition and subtraction is :

The least precise number present after the decimal point determines the number of significant figures in the answer.

Here the 44.67  has two significant digit after decimal point.So the answer will be reported as in with 2 significant figures after decimal point.

15.33833 L\approx 15.34 L

The chemical engineer should report average volume of 15.34 L.

5 0
2 years ago
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