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frosja888 [35]
2 years ago
6

If the pressure of each gas is increased at constant temp until condensation occurs, which gas will condense at the lowest press

ure?
There are 3 gases: methane, ethane, and butane. (formula, molar mass, temperature, and pressure given)
Chemistry
2 answers:
Phantasy [73]2 years ago
5 0
"Butane" is the gas among the following choices given in the question that will condense at a lower temperature, if <span>the pressure of each gas is increased at constant temp until condensation occurs. The reason behind such a conclusion is that butane has a stronger IMF. I hope the answer has come to your help.</span>
kiruha [24]2 years ago
3 0

Answer:

Butane

Explanation:

The only inter molecular attractions present between hydrocarbons is weak london dispersion forces. These forces are size dependent. More the surface area more the attractions.

Out of given gases butane is the highest member with greatest surface area among methane, ethane and itself.

So it will have higher intermoelcular london dispersion forces.

This makes it to condense easily at lower pressure as compared to methane and ethane.

You might be interested in
Which of the following compounds has the lowest boiling point?
sergejj [24]

Answer : The correct answer is option A : Diethyl ether

Explanation :

The boiling point of a compound depends on the intermolecular forces (IMF) of attractions present among its molecules.

Stronger the IMF, more difficult it is to separate the molecules. And hence the compound shows higher boiling point.

The most common types of IMF are

a) Hydrogen bonding : Hydrogen bonding occurs when a compound has hydrogen atom directly attached to strongly electro-negative atoms like O, N and F

Hydrogen bondings are the strongest IMF. Therefore compounds that have hydrogen bondings show higher boiling point.

In the given examples, 2-butanol and 4-octanol both have -OH group where H is directly attached to highly electro-negative O atom. As a result hydrogen bonding is present in these compounds.

Therefore they show higher boiling point.

b) Dipole interactions : These are seen in case of polar compounds.

c) London dispersion forces : These are present in all the compounds but they are predominant in case of non polar compounds.

Both diethyl ether and diphenyl ether predominantly show London dispersion forces. Since these forces are weaker as compared to other IMF, the molecules having london dispersion tend to have lower boiling points.

But the magnitude of dispersion forces increases as the molecular weight of the compound increases.

Therefore diphenyl ether which has a molecular weight of 170 g/mol has much stronger london dispersion forces as compared to diethyl ether which has a molecular weight of 74 g/mol

From above discussion, we can conclude that diethyl ether has the weakest intermolecular forces of attraction. Hence it has the lowest boiling point.


6 0
2 years ago
Convert 3.8 Km/sec to miles/year
weqwewe [10]
We are asked to convert from units of kilometer per second to units of miles per year. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1 mile is equal to 1609 meters and 1000 m is equal to 1 kilometer. Also, we will find that 3600 s is equal to 1 hr, 24 hr is equal to 1 day and 365 days is equal to 1 year. We do the conversion as follows:

3.8 km / s ( 1000 m / 1 km ) ( 1 mile / 1609 meters ) ( 3600 s / 1 hr ) ( 24 hr / 1 day ) ( 365 days / 1 year ) = 74479055.3 miles per year
5 0
2 years ago
The formula of complex ion formed when aluminum hydroxide dissolves in sodium hydroxide will be: Select the correct answer below
mojhsa [17]

Answer:

Al(OH)₃ +  OH⁻  →  Al(OH)₄⁻

The compound is called hydroxoaluminate.

Explanation:

Aluminiun Hydroxide → Al(OH)₃

NaOH → Sodium hydroxide.

The Al(OH)₃ is an amphoteric compound, while the NaOH is a strong base. When they react, we may think that, fist of all, the base can dissociate: NaOH  →  Na⁺  +  OH⁻

So the Al(OH)₃ will be a Lewis acid, as it can donate a pair of e⁻

Al(OH)₃ +  OH⁻  →  Al(OH)₄⁻

5 0
2 years ago
Suppose that 0.323 g of an unknown sulfate salt is dissolved in 50 mL of water. The solution is acidified with 6M HCl, heated, a
geniusboy [140]

Answer:

1) 41.16 % = 0.182 grams

2) The alkali cation is K+ , to form the salt K2SO4

Explanation:

Step 1: Data given

Mass of unknown sulfate salt = 0.323 grams

Volume of water = 50 mL

Molarity of HCl = 6M

Step 2: The balanced equation

SO4^2- + BaCl2 → BaSO4 + 2Cl-

Step 3: Calculate amount of SO4^2- in BaSO4

The precipitate will be BaSO4

The amount of SO4^2- in BaSO4 = (Molar mass of SO4^2-/Molar mass BaSO4)*100 %

The amount of SO4^2- in BaSO4 = (96.06 /233.38) * 100

= 41.16%

So in 0.443g of BaSO4 there will be 0.443 * 41.16 % = <u>0.182 grams</u>

<u />

<u />

2. If it is assumed that the salt is an alkali sulfate determine the identity of the alkali cation.

The unknown sulphate salt has 0.182g of sulphate. This means the alkali cation has a weight of 0.323-0.182 = 0.141g grams

An alkali cation has a chargoe of +1; sulphate has a charge of -2

The formula will be X2SO4 (with X = the unknown alkali metal).

Calculate moles of sulphate

Moles sulphate = 0.182 grams (32.1 + 4*16)

Moles sulphate = 0.00189 moles

The moles of sulphate = 0.182/(32.1+16*4)

The moles of sulphate = 0.00189 moles

X2SO4 → 2X+ + SO4^2-

For 2 moles cation we have 1 mol anion

For 0.00189 moles anion, we have 2*0.00189 = 0.00378 moles cation

Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.141 grams / 0.00378 grams

Molar mass = 37.3 g/mol

The closest alkali metal is potassium. (K2SO4 )

3 0
2 years ago
Two mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,00
AnnZ [28]

Answer:

Hello some parts of your question is missing

Two mixtures were prepared from three very narrow molar mass distribution polystyrene samples with molar masses of 10,000, 30,000 and 100,000 g mol−1 as indicated below: (a) Equal numbers of molecules of each sample (b) Equal masses of each sample (c) By mixing in the mass ratio 0.145:0.855 the two samples with molar masses of 10,000 and 100,000 g mol−1 For each of the mixtures, calculate the number-average and weight-average molar masses and comment upon the meaning of the values.

Answers:

a) 46.666.66 g/mol

b) 20930.23 g/mol

c)43333.33 g/mol

Explanation:

A)The equal number of molecules of each sample can be calculated using  Mn = \frac{n(M1 + M2 + M3)}{3n}

because for the number of molecules to be equal : n1 = n2 = n3 = n

Mn = 46666.66 g/mol

B ) To calculate the equal masses of each sample

we apply this equation

Mn = \frac{W1 + W2 +W3}{\frac{W1}{M1} +\frac{W2}{M2}+ \frac{W3}{M3}  }

ATTACHED BELOW IS THE REMAINING PART OF THE SOLUTION

7 0
2 years ago
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