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USPshnik [31]
2 years ago
5

Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc

using only on the physical properties of the water and lemonade. Which property is not an example of a physical property?
Group of answer choices

solubility

electrical conductivity

flammability

magnetism
Chemistry
1 answer:
vampirchik [111]2 years ago
6 0

Answer: i need help

Explanation:

You might be interested in
A solid sample of a compound and a liquid sample of the same compound are each tested for electrical conductivity. which test co
marshall27 [118]
If these are you choices: 
(1)  Both the solid and the liquid are good conductors.

(2)  Both the solid and the liquid are poor conductors.

(3)  The solid is a good conductor, and the liquid is a poor conductor.

(4)  The solid is a poor conductor, and the liquid is a good conductor. 

 Then the answer is number 4. This is because ionic compound conducts electricity when it is dissolved in water.

8 0
2 years ago
In pure water at 25 °C, the concentration of a saturated solution of CuF2 is 7.4 × 10−3 M. If measured at the same temperature,
Romashka-Z-Leto [24]

Answer:

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.

Explanation:

Consider the ICE take for the solubility of the solid, CuF₂ as:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -              -

At t =equilibrium      (x-s)                s           2s          

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

K_{sp}=s\times {2s}^2

K_{sp}=4s^3

Given  s = 7.4×10⁻³ M

So, Ksp is:

K_{sp}=4\times (7.4\times 10^{-3})^3

K_{sp}=4\times (7.4\times 10^{-3})^3

Ksp = 1.6209×10⁻⁶

Now, we have to calculate the solubility of CuF₂ in NaF.

Thus, NaF already contain 0.20 M F⁻ ions

Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:

                                  CuF₂    ⇄     Cu²⁺ +    2F⁻

At t=0                            x                 -            0.20

At t =equilibrium      (x-s')             s'         0.20+2s'         

The expression for Solubility product for CuF₂ is:

K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2

1.6209\times 10^{-6}={s}'\times ({0.20+2{s}'})^2

Solving for s', we get

<u>s' = 4.0×10⁻⁵ M</u>

<u>The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is  4.0×10⁻⁵ M.</u>

3 0
2 years ago
In the figure shown, AD, CE, and FB intersect at point F.
EleoNora [17]

Answer:

you need to send us the figure

Explanation:

7 0
1 year ago
Tell whether the following pairs of compounds are identical, constitutional isomers, stereoisomers, or unrelated. (a) cis-1,3-Di
Aleks04 [339]

Answer:

     (a) Constitutional Isomers

     (b) Constitutional Isomers

Explanation:

Constitutional isomers are also known with the name Structural Isomers. These are the compounds which have same chemical formula but differ in arrangement of atoms i.e. structure.

Both the compounds <em>cis-1,3-dibromocyclohexane</em> and <em>trans-1,4-dibromocyclohexane</em> have the same chemical formula C_{6} H_{10} Br_{2} but have different structure as shown in the image below.

In the second case the compounds <em>2,3-dimethylhexane</em> and <em>2,3,3-trimethylpentane</em>, both have same chemical formula C_{8} H_{18} but have different structures which is shown in the image below.

Thus it is clear that in both the groups (a) and (b) the given compounds are Constitutional Isomers.

7 0
2 years ago
Gaseous ICl (0.20 mol) was added to a 2.0 L flask and allowed to decompose at a high temperature:
Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

               2 ICl(g)   ⇄   I₂(g)    +    Cl₂(g)

Initially      0.20              -               -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React          x              x/2               x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

           (0.20 - x)          x/2             x/2

Notice that I have the concentration in equilibrium so:

0.20 - x = 0.060

x = 0.14

So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

Kc = 1.225x10⁻³ / 9x10⁻⁴

Kc = 1.36

8 0
1 year ago
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