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Alecsey [184]
2 years ago
13

Circle A has been dissected into 16 congruent sectors. The base of one sector is 1.95 units, and its height is 4.9 units. What i

s the approximate area of circle A?
circle A is dissected into 16 congruent sectors, one sector is highlighted
27.52 units2
48.92 units2
75.39 units2
76.44 units2
Mathematics
2 answers:
Nat2105 [25]2 years ago
8 0

Answer:

D.76.44 square units

Step-by-step explanation:

We are given that

Base of one sector=b=1.95 units

Height of sector=h=4.9 units

Total number of sectors=16

Area of one sector is equal to area of triangle (approximately)

Area of sector=\frac{1}{2}bh

Using the formula

Area of one sector=\frac{1}{2}(1.95)(4.9)=4.7775 square units

Area of circle A=16\timesarea of sector

Area of circle A=16\times 4.7775=76.44 square units

Hence,option D is true.

stira [4]2 years ago
3 0

Answer:

A=76.44\ units^{2}

Step-by-step explanation:

To find the approximate area of the circle, calculate the area of one sector and then multiply by 16

Remember that

The area of a triangle (one sector) is equal to

A=\frac{1}{2}(b)(h)

therefore

The approximate area of the circle is equal to

A=(16)\frac{1}{2}(1.95)(4.9)

A=76.44\ units^{2}

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horsena [70]

Answer:

y=3+x

Step-by-step explanation:

If you are ever unsure about how to proceed with a math problem, one thing I find very helpful is to imagine the scenario and sub in the numbers. That's always helped me

At the very beginning, when

x=0, Laurel hasn't bought any new hats yet, she owns 3 hats, so y=3.

After the first month, when x=1, laurel owns 3 hats, plus the 1 hat she just bought. She now owns y=3+1  hats.

After the second month, when

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hats.

Now, we can write the function.

y=3+x

7 0
2 years ago
If Emily made 75% of the baskets that she attempted if she made nine baskets how many attempt did she make
kvasek [131]
Twelve attempts were made at making a basket
6 0
2 years ago
The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

(0.36143)(0.36143) = 0.13063

4 0
2 years ago
E varies directly with the square root of C. If E=40 when C=25, find: C when E = 10.4
sukhopar [10]

Answer: C = 1.69

Step-by-step explanation:

E is proportional to √C

To remove proportionality, introduce a constant (k).

E = k × √C

From question,

E = 40 and C = 25

So,

40 = k ×√25

40 = k × 5

k = 8

Now,

C = ?

E = 10.4

k = 8

E = k × √C

10.4 = 8 × √C

10.4 / 8 = √C

( 10.4 / 8 ) ^ 2 = C

C = 1.69

6 0
2 years ago
Read 2 more answers
Square ABCD was translated using the rule (x, y) → (x – 4, y + 15) to form A'B'C'D'. What are the coordinates of point D in the
alisha [4.7K]
The translation is (x-4, y+15)

This means you would subtract 4 from the X coordinate and add 15 to the y coordinate.
 The original coordinates is (9,-8) 

The first number is X and the 2nd number is Y.

9-4 = 5

-8+15 = 7

The new location would be (5,7)

The answer is B.

4 0
2 years ago
Read 2 more answers
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