Question

If the intensity of an electromagnetic wave is 80 MW/m2, what is the amplitude of the magnetic field of this wave? (c=3.0×108m/s, μ0=4π×10−7T⋅m/A, ε0=8.85×10−12C2/N⋅m2)

Answer 1

Answer:

The the amplitude of the magnetic field of this wave is $2.4\times10^{5}\ N/C$

Explanation:

Given that,

Intensity $S= 80 Mw/m^2$

We need to calculate the amplitude of the magnetic field

Using formula of intensity

$S=\dfrac{E_{m}^2}{2c\mu_{0}}$

Where, $E_{m}$=Amplitude of an electromagnetic wave

c = speed of light

Put the value into the formula

$E_{m}^2=80\times10^{6}\times2\times3\times10^{8}\times4\pi\times10^{-7}$

$E_{m}=245598.40\ N/C$

$E_{m}=2.4\times10^{5}\ N/C$

Hence, The the amplitude of the magnetic field of this wave is $2.4\times10^{5}\ N/C$