answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zepler [3.9K]
2 years ago
3

Chameleons can rapidly project their very long tongues to catch nearby insects. The tongue of the tiny Rosette-nosed chameleon h

as the highest acceleration of a body part of any amniote (reptile, bird, or mammal) ever measured. In a somewhat simplified model of its tongue motion, the tongue, starting from rest, first undergoes a constant-acceleration phase with an astounding magnitude of 2500 m/s^2. This acceleration brings the tongue up to a final speed of 5.0 m/s. It continues at this speed for 22 m/s until it hits its target. What is the total distance traveled by the chameleon's tongue?
Physics
1 answer:
iragen [17]2 years ago
4 0

Answer:

0.115 m

Explanation:

Consider the motion of tongue during acceleration :

v₀ = initial velocity of the tongue = 0 m/s

v = final velocity of the tongue = 5 m/s

a = acceleration = 2500 m/s²

d = distance traveled during acceleration phase

Using the equation

v² = v₀² + 2 a d

5² = 0² + 2 (2500) d

d = 0.005 m

Consider the motion of tongue after it attains constant speed

d' = distance traveled during constant velocity

v = constant velocity = 5 m/s

t = time of travel = 22 ms = 0.022 s

using the equation

d' = v t

d' = 5 x 0.022

d' = 0.11 m

D = Total distance traveled by tongue

Total distance traveled by tongue is given as

D = d + d'

D = 0.005 + 0.11

D = 0.115 m

You might be interested in
A lawn sprinkler sprays water 8 feet at full pressure as it rotates 360 degrees. if the water pressure is reduced by 50%, what i
lina2011 [118]
The area of the sprinkles can be determined through the area of a circle that is pi * r^2 in which the given dimensions above are the radii, r. The second scenarios radius is only half of the original, that is 4 ft. In this case, we can compute the area of the second again. We calculate next the difference of two areas of circles. 
7 0
2 years ago
Suppose two astronauts on a spacewalk are floating motionless in space, 3.0 m apart. Astronaut B tosses a 15.0 kg IMAX camera to
marta [7]

Answer:

\frac{ 112.5}{15+m_{A}}=v_{f}

(we need the mass of the astronaut A)

Explanation:

We can solve this by using the conservation law of the linear momentum P. First we need to represent every mass as a particle. Also we can simplify this system of particles by considering only the astronaut A with an initial speed v_{iA} of 0 m/s and a mass m_{A} and the IMAX camera with an initial speed v_{ic} of 7.5 m/s and a mass m_{c} of 15.0 kg.

The law of conservation says that the linear momentum P (the sum of the products between all masses and its speeds) is constant in time. The equation for this is:

P_{i}=p_{ic}+p_{iA}\\P_{i}=m_{c}v_{ic}+m_{A} v_{iA}\\P_{i}=15*7.5 + m_{A}*0\\P_{i}=112.5 \frac{kg.m}{s}

By the law of conservation we know that P_{i} =P_{f}

For P_{f} (final linear momentum) we need to treat the collision as a plastic one (the two particles stick together after the encounter).

So:

P_{i} =P_{f}=112.5\\

112.5=(m_{c}+m_{A})v_{f}\\\frac{ 112.5}{m_{c}+m_{A}}=v_{f}\\\frac{ 112.5}{15+m_{A}}=v_{f}

3 0
2 years ago
A beam of unpolarized light with intensity I0 falls first upon a polarizer with transmission axis θTA,1 then upon a second polar
loris [4]

Answer:

The intensity I₂ of the light beam emerging from the second polarizer is zero.

Explanation:

Given:

Intensity of first polarizer = Io/2

For the second polarizer, the intensity is equal:

I_{2} =\frac{I_{o} }{2} (cos\theta )^{2} =\frac{I_{o} }{2} (cos90)^{2} =0

5 0
2 years ago
Find the intensity in decibels [i(db)] for each value of i. normal conversation: i = 106i0 i(db) = power saw a 3 feet: i = 1011i
White raven [17]

Answer:

Normal Conversation: i=106i0

i(dB)=60

Power saw a 3 feet: i=1011i0

i(dB)=110

Jet engine at 100 feet: i=1018i0

i(dB)=180

Explanation:

if these are the same as edge, then these are the answers! :)

8 0
2 years ago
Read 2 more answers
Which statement about electrons and atomic orbitals is NOT true?
balandron [24]

<em>An electron has the same amount of energy in all orbitals  is not true</em>

\boxed{\boxed{\bold{Further~explanation}}}

In an atom there are levels of energy in the skin and sub skin.

  • This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level.

So electrons that occupy the orbitals in the lowest sub-skin have the lowest energy level

  • In the principle of Pauli's prohibition it was stated that there are no two electrons in one atom that can have the same four quantum numbers.

So suppose that there are two electrons occupying one orbital can have the same main quantum number (n), azimuth (l) and magnetic (m), then the last quantum number that is the quantum spin number (s) must be different.

So that the two electrons are different from just the quantum spin number, even though the other quantum numbers are the same.

So in one orbital only a maximum of 2 electrons is occupied, because if there is a third electron, this third electron will have the same quantum spin number as the previous electron

  • The electron cloud is a visual representation of the location of electrons in an atom.

Orbital is the place around the nucleus where electrons may be found

Electron clouds show the state of electrons in their orbitals

So electron clouds can show the condition of all orbitals in an atom

The lowest energy level of an electron occupies a sub-skin of 1s which has only one orbital

Charging electrons in the sub skin uses the following sequence:

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.

Statement about electrons and atomic orbitals is not true is An electron has the same amount of energy in all orbitals

the electron configuration for barium (Ba) in noble-gas notation brainly.com/question/11147367

the formation of a bond.

brainly.com/question/11311275

quantum number

brainly.com/question/2292596

Keywords: the electron configuration, orbitals, atoms, energy, skin, sub skin, electron clouds

8 0
2 years ago
Read 2 more answers
Other questions:
  • Assume that a cloud consists of tiny water droplets suspended (uniformly distributed,
    13·1 answer
  • A recipe for candy requires that the liquid ingredients be stirred constantly until the liquid reaches a temperature of 140°C. W
    9·2 answers
  • Koala bears can eat only certain kind of Australian eucalyptus leaves.koalas are considered
    8·1 answer
  • A race car driver must average 200km/hr for four laps to qualify for a race. Because of engine trouble, the car averages only 17
    11·1 answer
  • Find the wavelength of the ultrasonic wave emitted by a bat if it has a frequency of 4.0 * 10^4 Hz.
    14·2 answers
  • Consider the static equilibrium diagram here. What is the angle F1 must make with the horizontal?
    13·2 answers
  • Rock X is released from rest at the top of a cliff that is on Earth. A short time later, Rock Y is released from rest from the s
    13·1 answer
  • A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e
    6·1 answer
  • Visualize five horizontal sedimentary strata exposed in a cliff or canyon wall identified by consecutive numbers, 1 being the lo
    9·2 answers
  • A positively charged particle Q1 = +45 nC is held fixed at the origin. A second charge Q2 of mass m = 4.5 μg is floating a dista
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!