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musickatia [10]
2 years ago
13

Ethan put $4000 in a 2-year CD paying 5% interest, compounded monthly. After 2 years, he withdrew all his money. What was the am

ount of the withdrawal? A. $4419.76 B. $4000.00 C. $4254.41 D. $4244.45
2b2t
Business
2 answers:
svp [43]2 years ago
7 0

Answer:

The total amount was $4419.76

Explanation:

The 5% of $4000 is $200 so after a 2 year period added to the amount the original deposit of $4000 then A is the correct and closest equal amount.

Sholpan [36]2 years ago
3 0

Answer: A. $4419.76

WHICH IS APPROXIMATELY $4420

Explanation: To calculate for compound interest we need the formula Amount A = P(1+r/n)^(nt)

P = principal = $4000

r = rate in decimal= 0.05

n= number of months= 24

t = number of years

A= 4000(1+(0.05/24))^(24*2)

A = 4000(1+(2.083*10^-3))^48

A= 4000(1.002083333)^48

A = 4000*1.105055962

A = $4420.22

Approximately $4420

You might be interested in
The Nelson Company has $1,750,000 in current assets and $700,000 in current liabilities. Its initial inventory level is $490,000
aleksley [76]

Answer:

(a) Short-term debt can increase by a maximum of $466,666.67 without pushing its current ratio below 1.9

(b) The firm's quick ratio after Nelson has raised the maximum amount of short-term funds is 1.34

Explanation:

Current assets = $1,750,000

Current liabilities = $700,000

Initial inventory level = $490,000

Current ratio = Current assets ÷ Current liabilities

= $1,750,000 ÷ $700,000 = 2.5

1.9 = (Current assets + \Delta{NP) ÷ (Current liabilities + \Delta{NP)

1.9 = ($1,750,000 + \Delta{NP) ÷ ($700,000 + \Delta{NP)

1.9 × ($700,000 + \Delta{NP) = ($1,750,000 + \Delta{NP)

$1,330,000 + 1.9\Delta{NP = $1,750,000 + \Delta{NP

0.9\Delta{NP =  $1,750,000 - $1,330,000

\Delta{NP = $466,666.67

Short-term debt can increase by a maximum of $466,666.67 without pushing its current ratio below 1.9

Quick ratio = (Current assets - Inventories) ÷ Current liabilities

= $937,500 ÷ $700,000

= 1.34

5 0
2 years ago
Water is flowing in a trapezoidal channel at a rate of Q 5 20 m3/s. The critical depth y for such a channel must satisfy the equ
irina1246 [14]

Answer / Explanation:

Kindly note that the question is incomplete. However, kindly find the complete question below and the answer.

Complete Question

Water is flowing in a trapezoidal channel at a rate of Q=20m³/s . The critical depth y for such a channel must satisfy the equation:

0 = 1 − Q² / gA³c . B Where g= 9.81m /s²  and Ac = the cross-section area can be related to depth y by B = 3+y and Ac = 3y+y²/2. Solve for the critical depth using (a). the graphical method,

Answer:

Given the equation,

0 = 1 − Q² / gA³c. B

Now substituting the given value g= 9.81m /s² , Q =20m³/s, B = 3+y, and Ac = 3y+y²/2,

We get:

0 = 1 - 20² / (9.81) ( 3y + y²/2)³ (3+y)

Hence we choose f(y) =  1 - 40.7747 / (3y + y²/2)³ . (3 + y) and solve for f(y) = 0

Therefore,

To solve using a graph, we take twelve sample points ( starting at y = 0.25 in step of 0.25m and plot a graph using MS- Excel. Kindly find the graph below.

2) As evident from the sample point and the graph function f(y) gets close to zero at y = 1.5, hence the root of f(y) = 0 is Xr = 1.5

6 0
2 years ago
In San Francisco, the typical pay in the installation, maintenance, and repair occupation exceeded the national average by 44 pe
saveliy_v [14]

Answer: Relative pay differential.

Explanation:

Relative pay differential is earnings compared with earnings of others doing the same job.

6 0
2 years ago
Instructions: Round your answers to 2 decimal places. If you are entering a negative number include a minus sign. a. Using the m
BabaBlast [244]

Answer:

The answer is below

Explanation:

The graph is attached below.

a) The price elasticity of demand is given by:

price elasticity of demand = \frac{\%\ change\ in\ quantity }{\%\ change\ in\ price}=\frac{\Delta Q}{\Delta P}

\Delta Q=\frac{Q_2-Q_1}{(Q_2+Q_1)/2} \\\\\Delta P=\frac{P_2-P_1}{(P_2+P_1)/2}

Price of elasticity demand =   \frac{\frac{Q_2-Q_1}{(Q_2+Q_1)/2} }{\frac{P_2-P_1}{(P_2+P_1)/2} }

Price of elasticity demand =   \frac{\frac{50-100}{(50+100)/2} }{\frac{4.5-4}{(4.5+4.0)/2} }=\frac{-0.6667}{0.1176} =5.7

Since the price of elasticity demand > 1, it is elastic

b) Price of elasticity demand =   \frac{\frac{200-300}{(200+300)/2} }{\frac{3-2}{(3+2)/2} }=\frac{-0.4}{0.4} =1

Since the price of elasticity demand = 1, it is unitary

c) Price of elasticity demand =   \frac{\frac{400-450}{(400+450)/2} }{\frac{1-0.5}{(1+0.5)/2} }=\frac{-0.1176}{0.6667} =0.18

Since the price of elasticity demand < 1, it is inelastic

6 0
2 years ago
Jim debt was reviewing the total accounts receivable. this month he received $80,000 from credit customers. this represented 40%
Eduardwww [97]
200,000 have to find what 10 percent is and multiply that by 10
4 0
2 years ago
Read 2 more answers
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