Newton's first law says that an object at rest tends to stay at rest while an object in motion stays in motion at a constant velocity unless acted upon by an outside force so the amount of force behind the defensive football player (N) was greater than the quarterback's so he was able to over power him which is also called unbalanced forces
Answer:
D. loss of volatiles to the atmosphere
Explanation:
The name magma designates matter in a semi-fluid state - resulting from the fusion of silicates containing dispersed solid gases and minerals and other compounds that make up the rocks, at temperatures between 700 and 1200 ° C - that forms the region beneath the crust. land. When it is inside the earth it is specifically named magma and lava when it is ejected to the surface
There are three systems by which magma can be produced on earth:
<u>
Temperature</u> rise by concentration of r<u>adioactive elements or by friction of lithospheric plates</u>.
<u>
Pressure decrease,</u> since the melting point decreases.
Adding <u>water</u> A rock begins to melt earlier if it contains water because the –OH groups effectively break the Si-O bonds.
A rock is formed by a set of minerals, each of which has a characteristic melting point so a rock does not have a single melting point but a temperature range in which the rock melts into parts, leaving others solid parts. Between the point at which a solid rock begins to melt and the melting end (liquid point) the rock is partially molten.
The rise of magmas depends on their physical-chemical conditions (viscosity, density, volatile element content), on the tectonic peculiarities of the region where they are found and on the rocks to be traversed. Acid magmas are light and viscous, rise easily and cause large deposits. The basic magmas, of greater density, are less viscous and ascend with greater difficulty than the previous ones.
Answer:
K_b = 78 J
Explanation:
For this exercise we can use the conservation of energy relations
starting point. Lowest of the trajectory
Em₀ = K = ½ mv²
final point. When it is at tea = 50º
Em_f = K + U
Em_f = ½ m v_b² + m g h
where h is the height from the lowest point
h = L - L cos 50
Em_f = ½ m v_b² + mg L (1 - cos50)
energy be conserve
Em₀ = Em_f
½ mv² = ½ m v_b² + mg L (1 - cos50)
K_b = ½ m v_b² + mg L (1 - cos50)
let's calculate
K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)
K_b = 36 +42.0
K_b = 78 J
Answer:
1.) 400s
2.) 1.875 m/s
3.) 1.125 m/s
Explanation:
Given that you traveled 150.meters south at a speed of 1.50m/s,
Time = distance/ speed
Substitute speed and distance into the formula
Time = 150/1.5
Time = 100 s
and then traveled 600. Meters north at a rate of 2.00 m/s.
Time = 600 / 2
Time = 300 s
1.) Total time = 100 + 300
Total time = 400 s
2.) The average speed will be total distance travelled over total time.
Total distance travelled = 150 + 600
Total distance travelled = 750 m
Substitute all the parameters into the formula
Average speed = 750/400
Average speed = 1.875 m/s
3.) Average velocity will be displacement over total time
Displacement = 600 - 150
Displacement = 450 m
Average velocity = 450/400
Average velocity = 1.125 m/s
Voltage = (current) x (resistance)
The voltage across THIS RESISTOR is
V = (0.050 A) x (0.1 ohm)
V = 0.005 v (5 millivolts)
