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artcher [175]
2 years ago
15

The formation of magma within Earth is NOT caused by which of the following processes? A. decompression (drop in pressure) B. ad

dition of volatiles C. transfer of heat from adjacent magma or very hot rocks D. loss of volatiles to the atmosphere
Physics
1 answer:
Lunna [17]2 years ago
8 0

Answer:

D. loss of volatiles to the atmosphere

Explanation:

The name magma designates matter in a semi-fluid state - resulting from the fusion of silicates containing dispersed solid gases and minerals and other compounds that make up the rocks, at temperatures between 700 and 1200 ° C - that forms the region beneath the crust. land. When it is inside the earth it is specifically named magma and lava when it is ejected to the surface

There are three systems by which magma can be produced on earth:

<u> Temperature</u> rise by concentration of r<u>adioactive elements or by friction of lithospheric plates</u>.

<u> Pressure decrease,</u> since the melting point decreases.

Adding <u>water</u> A rock begins to melt earlier if it contains water because the –OH groups effectively break the Si-O bonds.

A rock is formed by a set of minerals, each of which has a characteristic melting point so a rock does not have a single melting point but a temperature range in which the rock melts into parts, leaving others solid parts. Between the point at which a solid rock begins to melt and the melting end (liquid point) the rock is partially molten.

The rise of magmas depends on their physical-chemical conditions (viscosity, density, volatile element content), on the tectonic peculiarities of the region where they are found and on the rocks to be traversed. Acid magmas are light and viscous, rise easily and cause large deposits. The basic magmas, of greater density, are less viscous and ascend with greater difficulty than the previous ones.

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For an object starting from rest and accelerating with constant acceleration, distance traveled is proportional to the square of
natali 33 [55]

The problem states that the distance travelled (d) is directly proportional to the square of time (t^2), therefore we can write this in the form of:

d = k t^2

where k is the constant of proportionality in furlongs / s^2

 

<span>Using the 1st condition where d = 2 furlongs, t = 2 s, we calculate for the value of k:</span>

2 = k (2)^2

k = 2 / 4

k = 0.5 furlongs / s^2

The equation becomes:

d = 0.5 t^2

 

Now solving for d when t = 4:

d = 0.5 (4)^2

d = 0.5 * 16

<span>d = 8 furlongs</span>

<span>
</span>

<span>It traveled 8 furlongs for the first 4.0 seconds.</span>

8 0
2 years ago
With countercurrent flow, diffusion happened in all regions of the filter. Explain why
jeka94

Answer:

When the blood and the dialysate are flowing in the same direction, as the the dialysate and the blood move away from the region of higher concentration of the urea, to a region distant from the source, the concentration of urea in the blood stream and in the dialysis reach equilibrium and diffusion across the semipermeable membrane stops within the higher filter regions such as II, III, IV or V

However, for counter current flow, as the concentration of the urea in the blood stream becomes increasingly lesser the, it encounters increasingly unadulterated dialysate coming from the dialysate source, such that diffusion takes place in all regions of the filter

Explanation:

3 0
3 years ago
the minute hand on a clock is 9 cm long and travels through an arc of 252 degrees every 42 minutes. To the nearest tenth of a ce
Tanzania [10]

Answer:

The minutes hand travels 39.60 cm.

Explanation:

Note: a clock has a shape of a circle, the minutes hand is the radius, and the travel of the minutes hand forms a arc.

Length of an arc = ∅/360(2πr)

L = ∅/360(2πr).................... Equation 1π

Where L = length of an arc, ∅ = angle formed by an arc, r = radius of the arc.

Given:  ∅ = 252°, r = 9 cm, π = 3.143.

Substituting these values into equation 1,

L = 252/360(2×3.143×9)

L = 0.7×2×3.143×9

L = 39.60 cm.

Thus the minutes hand travels 39.60 cm.

4 0
2 years ago
Determine the maximum weight of the bucket that the wire system can support so that no single wire develops a tension exceeding
stellarik [79]
Let there be N number of wires.

Maximum tension a wire can withstand = 100 lb

so, Total tension N wires can withstand =  100 N

now, total tension in N wires = Maximum weight of bucket

100 N  = W

so, W = 100N

W is the weight of bucket and 100N is its maximum value.
8 0
2 years ago
A ball of mass m and radius R is both sliding and spinning on a horizontal surface so that its rotational kinetic energy equals
spin [16.1K]

Answer:

\frac{v_{cm}}{\omega} = 1.122\cdot R

Explanation:

According to the statement of the problems, the following identity exists:

K_{t} = K_{r}

\frac{1}{2}\cdot m \cdot v_{cm}^{2} = 0.63\cdot m \cdot R^{2} \cdot \omega^{2}

After some algebraic handling, the ratio is obtained:

\frac{v_{cm}^{2}}{\omega^{2}}=1.26\cdot R^{2}

\frac{v_{cm}}{\omega} = 1.122\cdot R

4 0
2 years ago
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