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strojnjashka [21]
2 years ago
7

A 3.0-kilogram mass is traveling in a circle of 0.20-meter radius with a speed of 2.0 meters per second. what is the centripetal

acceleration?
Physics
1 answer:
AysviL [449]2 years ago
6 0
Given: Mass m = 3.0 Kg     Radius r = 0.20 M       Velocity   =  2 m/s

Required:  Centripetal Acceleration ac = ?

Formula: Centripetal Force   Fc = mac   ac  = mv²/r

Fc = mv²/r

Fc = (3.0 Kg)(2 m/s)²/(0.2 m)

Fc = 60 N

Fc = mac   Derive ac or centripetal acceleration


ac = Fc/m

ac = 60 N/3.0 Kg

ac = 20 m/s²

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Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

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So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

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2 years ago
Two resistors ( 3 ohms & 6 ohms) in a series circuit with a power supply = 12 volts. The current through resistor 6 ohms is
Scorpion4ik [409]

In a series circuit . . .

-- The total resistance is the sum of the individual resistors.

-- The current is the same at every point in the circuit.

The total resistance in this circuit is (3Ω + 6Ω )  =  9Ω

The current at every point is (V/R) = (12v / 9Ω ) = <em>1.33 A</em> .

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1 year ago
The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a
Lunna [17]

Answer:

The change in power is 4400 W.

Explanation:

Given that,

Power = 10 kW

Speed = 10 m/s

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Given equation is,

F=kv

We know that,

The power is,

P=Fv

Put the value of F into the formula

P=(kv)v

P=kv^2

P\propto v^2

We need to calculate the new power

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Put the value into the formula

\dfrac{10}{P'}=(\dfrac{10}{12})^2

P'=(\dfrac{12}{10})^2\times10

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We need to calculate the change in power

Using formula of change in power

\Delta P=P'-P

Put the value into the formula

\Delta P=14.4-10

\Delta P=4.4\ kW

\Delta P=4.4\times1000

\Delta P=4400\ W

Hence, The change in power is 4400 W.

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The van of Hans and Frans is stuck on slippery ice, so they must get out and move it by hand. Hans pushes
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