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irakobra [83]
2 years ago
7

3) A defense football player on one team tackles the other team’s quarterback, who is running down the field. The quarterback is

pushed to the ground by the defensive player. 4) apply Newton’s first law to explain what happened?
Physics
1 answer:
alisha [4.7K]2 years ago
5 0
Newton's first law says that an object at rest tends to stay at rest while an object in motion stays in motion at a constant velocity unless acted upon by an outside force so the amount of force behind the defensive football player (N) was greater than the quarterback's so he was able to over power him which is also called unbalanced forces
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Sonia was experimenting with electric charges. She tied two inflated balloons together, held them next to each other, and rubbed
AVprozaik [17]

Answer:

Sonia will experience repulsion in two balloons

Explanation:

Here when we rub the balloon with the woolen cloth then due to friction between the cloth and balloon electrons from balloon will transfer to woolen cloth.

Due to transfer of electron the balloon will get positive charge which is given by

Q = Ne

so here since both balloons are rubbed against woolen cloth so both balloon will get some positive charge

now we know by the property of charge that two similar charges will always repel each other so here two balloons will repel each other after they rubbed against woolen cloth.

6 0
2 years ago
Read 2 more answers
1. For each of the following scenarios, describe the force providing the centripetal force for the motion: a. a car making a tur
GenaCL600 [577]

Complete Question

For each of the following scenarios, describe the force providing the centripetal force for the motion:

a. a car making a turn

b. a child swinging around a pole

c. a person sitting on a bench facing the center of a carousel

d. a rock swinging on a string

e. the Earth orbiting the Sun.

Answer:

Considering a

    The force providing the centripetal force is the frictional force on the tires \

          i.e  \mu mg  =  \frac{mv^2}{r}

    where \mu is the coefficient of static friction

Considering b

   The force providing the centripetal force is the force experienced by the boys  hand on the pole

Considering c

     The force providing the centripetal force is the normal from the bench due to the boys weight

Considering d

     The force providing the centripetal force is the tension on the string

Considering e

      The force providing the centripetal force is the force of gravity between the earth and the sun

Explanation:

6 0
2 years ago
A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass
Vlada [557]
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg

choose A

6 0
2 years ago
The difference between the two molar specific heats of a gas is 8000J/kgK. If the ratio of the two specific heats is 1.65, calcu
Serjik [45]

Answer:

sorry

Explanation:

pls search on google

4 0
2 years ago
An object initially at rest experiences a constant horizontal acceleration due to the action of a resultant force applied for 10
Marianna [84]

Answer:

a = 18.28 ft/s²

Explanation:

given,

time of force application, t= 10 s

Work = 10 Btu

mass of the object = 15 lb

acceleration, a =  ? ft/s²

1 btu = 778.15 ft.lbf

10 btu = 7781.5 ft.lbf

m = \dfrac{15}{32.174}\ slug

m = 0.466 slug

now,

work done  is equal to change in kinetic energy

W = \dfrac{1}{2} m (v_f^2-v_i^2)

7781.5 = \dfrac{1}{2}\times 0.466\times v_f^2

 v_f = 182.75\ ft/s

now, acceleration of object

  a = \dfrac{v_f-v_o}{t}

  a = \dfrac{182.75-0}{10}

         a = 18.28 ft/s²

constant acceleration of the object is equal to 18.28 ft/s²

3 0
2 years ago
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