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Katyanochek1 [597]
2 years ago
4

You have read a new brand of hair tonic is supposed to contain lead (an ingredient in Grecian Formula). Devise a simple test to

confirm the presence or absence of lead in that hair tonic. Use your observation from the experiments you have performed.
Chemistry
1 answer:
QveST [7]2 years ago
3 0

Explanation:

If the hair tonic contains lead, then these test will be positive:

1. To the tonic, add dilute sulfuric acid. The appearance of white precipitate confirms lead.

<u>Pb²⁺ + SO₄²⁻ ⇒ PbSO₄ (White precipitate)</u>

2. Add 2-3 mL of potassium chromate solution to the tonic. The appearance of yellow precipitate confirms lead.

<u>Pb²⁺ + CrO₄²⁻ ⇒ PbCrO₄ (Yellow precipitate)</u>

3. To the tonic, add 2-3 mL of potassium iodide solution. The appearance of yellow precipitate confirms lead.

<u>Pb²⁺ + 2I⁻ ⇒ PbI₂ (Yellow precipitate)</u>

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In a container containing co, h2, and o2, what is the mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fracti
almond37 [142]
Thank you for posting your question here at brainly. The <span>mole fraction of co if the h2 mole fraction is 0.22 and the o2 mole fraction is 0.58 is 0.20, below is the solution:
</span>
mole fraction CO + mole fraction H2 + mole fraction O2 = 1 

mole fraction CO = 1 - ( 0.22 + 0.58)=0.20
6 0
2 years ago
The successive ionization energies of a certain element are I1= 577.9 kJ/mol, I2 = 1820 kJ/mol, I3= 2750 kJ/mol, I4 = 11,600 kJ/
Maksim231197 [3]

Answer:

Aluminium

Explanation:

Ionization energy is the amount of energy needed to remove an electron from a gaseous atom to form a gaseous ion.

The difference between the third and fourth ionization energies is great. This indicates a group III element which is in the third period.

This element is Aluminium (Al)

6 0
2 years ago
It takes energy to ionize any atom. It takes progressively more and more energy for each successive electron that is removed and
IrinaVladis [17]

Answer:

Removal of Third Electron

Explanation:

a major jump is required to remove the third electron. In general, successive ionization energies always increase because each subsequent electron is being pulled away from an increasingly more positive ion.

Ionization energy increases from bottom to top within a group, and increases from left to right within a period.

5 0
2 years ago
Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
      = 176.15 kJ - 84.78 kJ = 91.38 kJ 
 





 
6 0
2 years ago
Read 2 more answers
Heavy nuclides with too few neutrons to be in the band of stability are most likely to decay by what mode?
Margarita [4]

Answer:

Positron emission

Explanation:

Positron emission involves the conversion of a proton to a neutron. This process increases the mass number of the daughter nucleus by 1 while its atomic number remains the same. The new neutron increases the number of neutrons present in the daughter nucleus hence the process increases the N/P ratio.

A positron is usually ejected in the process together with an anti-neutrino to balance the spins.

6 0
2 years ago
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