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Triss [41]
2 years ago
3

A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 65 Btu of heat is tr

ansferred to the water, and heat losses from the side walls amount to 8 Btu. The piston rises as a result of evaporation, and 5 Btu of work is done by the vapor. Determine the change in the energy of the water for this process.
Engineering
2 answers:
DaniilM [7]2 years ago
3 0

Answer:

The change in energy=47 Btu

Explanation:

Given that

Heat transfer to the water=60 Btu

Heat loss from the walls=8 Btu

Work done by the system= 5 Btu

From first law of thermodynamics

   Q=ΔU+W

Here Q =Heat transfer

        ΔU=Change in internal energy

         W=Work transfer

From standard sing convention

if heat is added to the system then it will taker as positive and if  heat is escaping from the system then it will taker as negative.

If work is done by system then it will take as positive and if work is done on system then it will take as negative.

So net heat transfer in the system(Q)=60-8 Btu

                                                       Q =52 Btu

Work done by system(W)= 5 Btu

Now by putting the values

 Q=ΔU+W

52= ΔU+5

ΔU=47 Btu

So the change in energy=47 Btu

8090 [49]2 years ago
3 0

Answer:

dU = 52 kJ

Explanation:

Given:

During the process,

Heat transferred to water = 65 kJ

Heat loss from side = 8 kJ

Therefore, Resultant Heat transferred to water :

dQ = 65 KJ - 8K J = 57 kJ

Work done by the Vapour:

dW = 5 kJ

Let,

from thermo-dynamic first law

we have,

dQ = dU + d W

dU = dQ - dW

     =   57 kJ - 5 kJ    

     = 52 kJ

Thus, change in energy for this system is :

dU = 52 kJ

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Angelina_Jolie [31]

Answer:

The time taken will be "1 hour 51 min". The further explanation is given below.

Explanation:

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= 1.25 mm

Velocity (v):

= 40 mm/s

Now,

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= 38\times 38 \ mm^2

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The area covered every \second will be:

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= 50 \ mm^2

The time required to deposit one layer will be:

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= 28.88 \ sec

The time required for one layer will be:

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∴ Total times required for one layer will be:

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= 43.88 \ sec

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2 years ago
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A should be it or b
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On a summer day in New Orleans, Louisiana, the pressure is 1 atm: the temperature is 32°C; and the relative humidity is 95 perce
FinnZ [79.3K]

Answer:

Δw =7.95 kg/1000m^3

q = 62362.3 kg/1000m^3

Explanation:

To solve this problem we first need to use the psycrometric chart to determine the enthalpy h1, specific volume vi and absolute humidity col by using the given temperature T1 = 32°C and the relative humidity Ф1 = 95%.  

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w_1 = 0.02905

We will also need the enthalpy h2 and the absolute humidity w_2 at the exit point. We will again use the pyscrometric chart and the given temperature T_2 = 24°C. From the problem we also know that the exit relative humidity is = 60%.  

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We need to express the final results in units per 1000 m^3. To do that we will need the mass m of this volume of air V and to calculate that we will use the given pressure p = 1 atm = 101.3 kPa.  

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Δw =0.00687 kg/kg* 1157kg/1000m^3

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q = 53.9 kJ/kg * 1157kg/1000m^3

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An employee’s total weekly pay equals the hourly wage multiplied by the total number of regular hours plus any overtime pay. Ove
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Answer:

Explanation:

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