Answer: The concentration of excess in solution is 0.017 M.
Explanation:
1.
moles of
1 mole of give = 1 mole of
Thus 0.019 moles of give = 0.019 mole of
2. moles of
According to stoichiometry:
1 mole of gives = 2 moles of
Thus 0.012 moles of give =
moles of
As 1 mole of neutralize 1 mole of
0.019 mole of will neutralize 0.019 mole of
Thus (0.024-0.019)= 0.005 moles of will be left.
Thus molarity of in solution is 0.017 M.
Sodium-22 remain : 1.13 g
<h3>Further explanation </h3>The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually, radioactive elements have an unstable atomic nucleus.
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
half-life = t 1/2=2.6 years
T=15.6 years
No=72.5 g
A 0.200 M of K2SO4 solution is produced by diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL.
<u>Explanation</u>:
M1 V1 = M2 V2
where,
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
M1 V1 = M2 V2
20.0 mL 5.00 M = M2
500.0 mL
M2 = (20.0 mL 5.00 M) / 500.0 mL
M2 = 0.200 M.
Hence A 0.200 M of K2SO4 solution is produced by diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL.