Question

Calculate the volume (in mL) of 0.00500 M KCl solution that needs to be added to a 50.0 mL volumetric flask and diluted with deionized (DI) water in order to prepare a calibration standard solution with a concentration of 1.50 x 10-4 M KCl. As part of your preparation for performing this experiment, repeat this calculation for each of the calibration standards you will need to prepare and record the information in your lab notebook so that you have it ready during the lab session.

Answer 1

Explanation:

As the given data is as follows.

     $M_{1}$ = 0.005 M,       $M_{2} = 1.50 \times 10^{-4}$

     $V_{1}$ = ? mL,        $V_{2}$ = 50.0 mL

When the number of moles of the species are equal then the formula will be as follows.

                     $M_{1}V_{1} = M_{2}V_{2}$

          $0.005 \times V_{2} = 1.50 \times 10^{-4} \times 50.0 mL$

                  $V_{2}$ = 1.50 mL

Thus, we can conclude that volume that needs to be added is 1.50 mL.