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2 years ago

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Diamond has an index of refraction of 2.419. What is the critical angle for internal reflection inside a diamond that is in liqu

id of index of refraction n=2? A) 15.4° B) 55.8° C) 26° D) 20° E) 39°

1 answer:

Anestetic [448]2 years ago

7 0

Answer:

B) 55.8°

Explanation:

n₁ = Refractive index of liquid = 2

n₂ = Refractive index of diamond = 2.419

Here it can be seen that the light ray is in the more dense medium and approaching the less dense medium which is a case of total internal reflection.

Critical angle

$\theta_r=sin^{-1}\frac{n_1}{n_2}\\\Rightarrow \theta_r=sin^{-1}\frac{2}{2.419}\\\Rightarrow \theta_r=sin^{-1}0.826\\\Rightarrow \theta_r=55.7701^{\circ}$

∴ Critical angle is 55.8°

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2 years ago

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1 year ago