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harkovskaia [24]
2 years ago
11

Which statements are true regarding the diagram? Check all that apply.

Mathematics
2 answers:
gulaghasi [49]2 years ago
6 0

Answer:

2, 4, 6

B, D, F

Step-by-step explanation:

Ray C E is contained on line m.

Ray AD is the same as ray AC.

∠ECB is created from Ray C E and Ray C B.

Vesnalui [34]2 years ago
5 0

Answer:

2.CE is contained on the line m.

4.Ray AD is the same as ray AC.

6.Angle ECB is created from CE and CB.

Step-by-step explanation:

We are given that a diagram .

We have to find which statement are true about the given diagram.

1.CB is contained on the line n.

CB is not contained on the line n because point C and B are not lying on the line n.

Therefore, it not true.

2.CE is contained on the line m.

CE is contained on the line m because point C and E are lying on the line m.

Therefore, it is true.

3.Ray BC is the same as ray CB.

A ray  has one initial point and has no terminal point.It can extend to infinity .

Ray CB has initial point C and it extends from the point B.

But there is no BC ray.

Therefore, it is not true.

4.Ray AD is the same as ray AC.

AD is a ray but AC is also

AD and AC are same because both have initial point A and extend in the same direction.

5.Angle EAD is created from AE and DA.

It is not true because angle EAD is formed by ray AE and ray AD not ray DA.

6.Angle ECB is created from CE and CB.

It is true because angle ECB is formed by ray EC and ray BC.

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ΔABC is dilated using a scale factor of 12 to produce ΔA'B'C'. Select all of the statements that apply to the transformation.
GalinKa [24]

Answer:

Options (3) and (6)

Step-by-step explanation:

ΔABC is a dilated using a scale factor of \frac{1}{2} to produce image triangle ΔA'B'C'.

Since, dilation is a rigid transformation,

Angles of both the triangles will be unchanged or congruent.

m∠A = m∠A' and m∠B = m∠B'

Since, sides of ΔA'B'C' = \frac{1}{2} of the sides of ΔABC

Area of ΔA'B'C' = \frac{1}{2}(\text{Area of triangle ABC})

Area of ΔABC > Area of ΔA'B'C'

Since, angles of ΔABC and ΔA'B'C' are congruent, both the triangles will be similar.

ΔABC ~ ΔA'B'C'

Therefore, Option (3) and Option (6) are the correct options.

3 0
1 year ago
A coordinate plane with a straight line with a positive slope. The line starts at (0, 0) and passes through points labeled A at
g100num [7]

Answer:

1...2....0.5 are the answers

Step-by-step explanation:

dont listen to the other its wrong

8 0
1 year ago
Read 2 more answers
Find all points of intersection of the given curves. (Assume 0 ≤ θ ≤ 2π and r ≥ 0. Order your answers from smallest to largest θ
DerKrebs [107]

Answer:

∅1=15°,∅2=75°,∅3=105°,∅4=165°,∅5=195°,∅6=255°,∅7=285°,

∅8=345°

Step-by-step explanation:

Data

r = 8 sin(2θ), r = 4 and r=4

iqualiting; 8.sin(2∅)=4; sin(2∅)=1/2, 2∅=asin(1/2), 2∅=30°, ∅=15°

according the graph 2, the cut points are:

I quadrant:

0+15° = 15°

90°-15°=75°

II quadrant:

90°+15°=105°

180°-15°=165°

III quadrant:

180°+15°=195°

270°-15°=255°

IV quadrant:

270°+15°=285°

360°-15°=345°

No intersection whit the pole (0)

7 0
2 years ago
a water tank holds 24,000 gallons how many hours will it take for two thirds of the water to be used if the water is used at an
melomori [17]
In this question there are several important information's worth noting.Based on these information's the answer can be easily found. It is given that the total capacity of the tank is 24000 gallons. in 24 hours or in 1 day the amount of water used is 650 gallons. The question requires us to find the time it will take to use 2/3 rd of the water in the tank.
then
2/3 rd water in respect to total water in tank = (2/3) * 24000
                                                                       = 16000
So 2/3 rd water of full tank is equivalent to 16000 gallons.
Now
650 gallons of water is used in = 24 hours
So
16000 gallons of water will be used in = (24/650) * 16000
                                                             = 590.77 hours
So it will take 590.77 hours to consume 2/3rd of the total water present in the tank.
6 0
1 year ago
The top of a ladder is 4m up a vertical wall.The bottom is 2m from the wall.The coordinate axes are the wall and the horizontal
mash [69]

Answer:

Part a) y=-2x+4

Part b) The coordinates of the point are (\frac{4}{3},\frac{4}{3})

Step-by-step explanation:

Part a) Find the equation representing the ladder

we have the ordered pairs

(0,4) and (2,0)

Find the slope

m=(0-4)/(2-0)=-2

Find the equation of the line in slope intercept form

y=mx+b

we have

m=-2\\b=4

substitute

y=-2x+4

Part b) A square box just fits under the ladder.Find the coordinates of the point where the box touches the ladder.

If the box is a square

the x-coordinate of the point where the box touches the ladder must be equal to the y-coordinate

x=y

y=-2x+4

substitute

x=-2x+4\\3x=4\\x=\frac{4}{3}

y=x=\frac{4}{3}

therefore

The coordinates of the point are (\frac{4}{3},\frac{4}{3})

6 0
1 year ago
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