Answer:
( x y -6)² = x² y² - 12 xy + 36
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the expression ( x y -6)²
Apply formula (a-b)² = a² -2ab + b²
( x y -6)² = (xy)² - 2 × xy× 6 + (6)²
= x² y² - 12 xy + 36
( x y -6)² = x² y² - 12 xy + 36
I think the answer is AB and AE but I need a picture to be sure.
Answer:
<em>The distance between the two villages is 16.5 Km</em>
Step-by-step explanation:
<u>Constant Speed Motion</u>
It's a type of motion in which the distance of an object changes by an equal amount in every equal period of time.
If v is the constant speed, the object travels a distance x in a time t, given by the equation:
x=vt
Amar cycles at v=18 Km/h for t=55 minutes. We need to calculate the distance traveled between the two villages.
Since the speed and the time are given in different units, we convert the time to hours, recalling that 1 hour=60 minute.
t=55 min = 55/60 hours
For the sake of precision, we won't operate the division so far. Compute the distance:
x=18 *55/60=16.5 Km
The distance between the two villages is 16.5 Km
Answer:
<em>The probability is 42%</em>
Step-by-step explanation:
<u>Conditional Probability</u>
It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).
If P(A) is the probability of occurrence of A, 
is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:
We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.
The probability that a randomly selected band member plays the trumpet is
The probability that he or she has both attributes is
Thus, the required conditional probability is
The probability is 42%
Answer:
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Step-by-step explanation:
Intern No. of Breast
Number Exams Performed X²
1 30 900
2 40 1600
3 8 64
4 20 400
5 26 676
6 35 1225
7 35 1225
8 20 400
9 25 625
<u>10 20 400 </u>
<u> </u><u> ∑ 259 ∑ 7515</u>
Mean= X`= ∑x/n= 259/10= 25.9
Variance = s²= 1/n-1[∑X²- (∑x)²/n]
= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]
= 806.9/9=89.655= 89.66
Standard Deviation= √89.655= 9.4687
Hence
The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262
The 95 % Confidence interval is given by
x`±t(∝,n-1) s/√n
So Putting the values
25.9± 2.262( 9.4687/√10)
= 25.9 ±2.262 (2.9943)
= 25.9 ± 6.7730
= 25.9 +6.7730=32.6730
25.9 -6.7730= 19.1269
= 19.1269, 32.6730
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
