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pychu [463]
1 year ago
8

Calcium reacts with bromine to form calcium bromide. 2.1 Which atom will lose electrons? 2.2 How many electrons will it lose? 2.

3 Name the element that will gain electrons. 2.4 How many electrons does this atom gain? 2.5 Write down the symbol for each of the ions formed. 2.6 Write the chemical formula for calcium bromide.
Chemistry
1 answer:
Juli2301 [7.4K]1 year ago
8 0

<u>Answer:</u>

<u>For 2.1:</u> Calcium atom will loose electrons.

<u>For 2.2:</u> It will loose 2 electrons.

<u>For 2.3:</u> Bromine atom will gain electrons.

<u>For 2.4:</u> It will gain 1 electron.

<u>For 2.5:</u> The ions formed are Ca^{2+}\text{ and }Br^-

<u>For 2.6:</u> The chemical formula is CaBr_2

<u>Explanation:</u>

Calcium bromide is formed by the combination of calcium and bromine atoms. This compound is ionic compound because electrons get transferred from one atom to another atom.

Calcium is the 20th element of the periodic table. It is a metal and it looses its electrons. The electronic configuration for this element is 1s^22s^22p^63s^23p^64s^2

This element will loose 2 electrons and forms Ca^{2+} ion.

Bromine is the 35th element of the periodic table. It is a non-metal and it gains electrons. The electronic configuration for this element is [Ar]4s^23d^{10}4p^5

This element will gain 1 electron and forms Br^- ion.

The chemical formula for the given compound is CaBr_2

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Assuming equal concentrations of conjugate base and acid, which one of the following mixtures is suitable for making a buffer so
BartSMP [9]

Answer:

NH₃/NH₄Cl

Explanation:

We can calculate the pH of a buffer using the Henderson-Hasselbalch's equation.

pH=pKa+log\frac{[base]}{[acid]}

If the concentration of the acid is equal to that of the base, the pH will be equal to the pKa of the buffer. The optimum range of work of pH is pKa ± 1.

Let's consider the following buffers and their pKa.

  • CH₃COONa/CH3COOH (pKa = 4.74)
  • NH₃/NH₄Cl (pKa = 9.25)
  • NaOCl/HOCl (pKa = 7.49)
  • NaNO₂/HNO₂ (pKa = 3.35)
  • NaCl/HCl Not a buffer

The optimum buffer is NH₃/NH₄Cl.

4 0
1 year ago
How many moles of O2 would be required to generate 13.0 mol of NO₂ in the reaction below assuming the reaction has only 73.3% yi
Airida [17]

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Mmmmmmmmmmmmmmm

Explanation:

4 0
1 year ago
Calculate the number of chloride ions in 6.8 g of zinc chloride
Bumek [7]

Answer:

The correct answer is 0.300 * 10^23 ions.

Explanation:

Based on the given question, there is a need to find the number of chloride ions in the mentioned 6.8 grams of zinc chloride compound.  

The moles of zinc chloride (ZnCl2) is,  

= mass of zinc + 2 mass of chlorine

= 65.38 + 2 (35.45)

=65.38 + 70.90

= 136.28 grams (The molecular mass of zinc is 65.38 and the molecular mass of chlorine is 35.45)

Thus, 136.28 g of ZnCl2 contains 70.90 grams of chlorine

Therefore, 6.8 grams of ZnCl2 will comprise = (70.90/136.28) * 6.8

= 3.537 g of chlorine

70.90 g of Cl comprise 6.022*10^23 chlorine, thus, 3.537 g of Cl will comprise (6.022*10^23/70.90) * 3.537

= 0.300 * 10^23 ions of chlorine.  

3 0
2 years ago
What is the concentration of an alcl3 solution if 150. ml of the solution contains 550. mg of cl- ion?
valina [46]

The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M


calculation


concentration = moles /volume in liters


volume in liters = 150 /1000= 0.15 L


number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-


find the moles of Cl^- formed

moles =mass/molar mass

mass in grams= 550/ 1000 =0.55 grams

molar mass of Cl^- =35.5 g/mol


moles is therefore= 0.55/35.5 =0.0155 moles


by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles



concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M

6 0
2 years ago
What pressure (in atm) would be exerted by 76 g of fluorine gas (f2) in a 1.50 liter vessel at -37oc? (a) 26 atm(b) 4.1 atm(c) 1
nirvana33 [79]

<span>Let's assume that the F</span>₂ gas has ideal gas behavior. 

<span> Then we can use ideal gas formula,
PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol</span>⁻¹ K⁻<span>¹) and T is temperature in Kelvin.</span>


Moles = mass / molar mass


Molar mass of F₂ = 38 g/mol

Mass of F₂  = 76 g

Hence, moles of F₂ = 76 g / 38 g/mol = 2 mol

<span>
P = ?
V = 1.5 L = 1.5 x 10</span>⁻³ m³

n = 2 mol

R = 8.314 J mol⁻¹ K⁻<span>¹
T = -37 °C = 236 K

By substitution,
</span>

P x 1.5 x 10⁻³ m³ = 2 mol x 8.314 J mol⁻¹ K⁻¹ x 236 K

                         p = 2616138.67 Pa

                         p = 25.8 atm = 26 atm


Hence, the pressure of the gas is 26 atm.

Answer is "a".

<span>

</span>
5 0
1 year ago
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