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HACTEHA [7]
2 years ago
3

A turtle takes 3.5 minutes to walk 18 m toward the South along a deserted highway. A truck driver stops and picks up the turtle.

The driver takes the turtle to a town 1.2 km to the North with an average speed of 12 m/s. What is the magnitude of the average velocity of the turtle for its entire journey?
Physics
1 answer:
grin007 [14]2 years ago
5 0

Answer:

3.8 m s⁻¹.

Explanation:

Average velocity = Total displacement / Total time

Initial displacement = + 18 m towards the south

Final displacement = - 1.2 km = - 1200 m towards the north ( sign changed due to opposite direction )

Total displacement = -1200 + 18 = - 1182 m

Initial time = 3.5 minutes

= 3.5 x 60 = 210 s

Final time = distance / velocity

= 1200 / 12

= 100 s

Total time =100 + 210

= 310 s

So , average velocity of turtle

= -1182 / 310 = 3.8 m /s

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A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

3000²)

A = 17.5*10^-3/ 1.13*10^-5

= 15.5*10^-2m²

Area= π r ²

15.5E-2/3.142 = r²

2.2*10^2m

Explanation:

5 0
2 years ago
A soccer ball kicked with a force of 13.5 n accelerates at 6.5 m/s^2 to the right. what is the mass of the ball?
natita [175]

Answer:

2.08 kg

Explanation:

Newton's second law states that the acceleration of an object is proportional to the force applied to the object, according to the equation:

F=ma

where F is the force applied, m is the mass of the object and a its acceleration.

In this situation, the soccer ball is kicked with a force F=13.5 N and its acceleration is a=6.5 m/s^2, therefore its mass is

m=\frac{F}{a}=\frac{13.5 N}{6.5 m/s^2}=2.08 kg

6 0
2 years ago
ASK YOUR TEACHER A 2.0-kg mass swings at the end of a light string with the length of 3.0 m. Its speed at the lowest point on it
Nadya [2.5K]

Answer:

  K_b = 78 J

Explanation:

For this exercise we can use the conservation of energy relations

starting point. Lowest of the trajectory

        Em₀ = K = ½ mv²

final point. When it is at tea = 50º

        Em_f = K + U

        Em_f = ½ m v_b² + m g h

where h is the height from the lowest point

        h = L - L cos 50

        Em_f = ½ m v_b² + mg L (1 - cos50)

energy be conserve

        Em₀ = Em_f

         ½ mv² = ½ m v_b² + mg L (1 - cos50)

         K_b = ½ m v_b² + mg L (1 - cos50)

let's calculate

          K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)

          K_b = 36 +42.0

          K_b = 78 J

4 0
2 years ago
While working on her science fair project Venus connected a battery to a circuit that contained a light bulb. Venus decided to c
Dmitriy789 [7]
<h2>Answer:</h2>

<u>A) Increase the voltage by adding a bigger battery </u>

<h2>Explanation:</h2>

According to Ohm's law

V = IR

where V is voltage, I is current and R is the resistance. If we write the equation for resistance we would get

R= V / I

Here we can see that Voltage is directly proportional to Resistance so in order to keep the balance if we increase the resistance then we must increase the voltage to keep the current constant.


4 0
2 years ago
Read 2 more answers
If 56 grams of carbon monoxide burns in oxygen to produce 88 grams of carbon dioxide, the mass of oxygen involved in the reactio
pentagon [3]

Answer : The mass of oxygen involved in the reaction is, 32 grams.

Explanation : Given,

Mass of carbon monoxide = 56 g

Mass of carbon dioxide = 88 g

Molar mass of carbon monoxide (CO) = 28 g/mole

Molar mass of oxygen (O_2) = 32 g/mole

First we have to calculate the moles of carbon monoxide.

\text{Moles of CO}=\frac{\text{Mass of CO}}{\text{Molar mass of CO}}=\frac{56g}{28g/mole}=2moles

Now we have to calculate the moles of oxygen gas.

The balanced chemical reaction will be,

2CO+O_2\rightarrow 3CO_2

From the balanced chemical reaction, we conclude that

2 moles of CO react with 1 mole of O_2

So, the moles of O_2 = 1 mole

Now we have to calculate the mass of oxygen.

\text{Mass of }O_2=\text{Moles of }O_2\times \text{Molar mass of }O_2

\text{Mass of }O_2=1mole\times 32g/mole=32g

Therefore, the mass of oxygen involved in the reaction is, 32 grams.

5 0
2 years ago
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