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1 year ago

A soccer ball kicked with a force of 13.5 n accelerates at 6.5 m/s^2 to the right. what is the mass of the ball?

Physics

1 answer:

natita [175]1 year ago

6 0

Answer:

2.08 kg

Explanation:

Newton's second law states that the acceleration of an object is proportional to the force applied to the object, according to the equation:

$F=ma$

where F is the force applied, m is the mass of the object and a its acceleration.

In this situation, the soccer ball is kicked with a force F=13.5 N and its acceleration is a=6.5 m/s^2, therefore its mass is

$m=\frac{F}{a}=\frac{13.5 N}{6.5 m/s^2}=2.08 kg$

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A 225 kg red bumper car is moving at 3.0 m/s. It hits a stationary 180 kg blue bumper car. The red and blue bumper cars combine

Alex Ar [27]

Given

m1(mass of red bumper): 225 Kg

m2 (mass of blue bumper): 180 Kg

m3(mass of green bumper):150 Kg

v1 (velocity of red bumper): 3.0 m/s

v2 (final velocity of the combined bumpers): ?

The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:

Pa= Pb

Where Pa is the momentum before collision and Pb is the momentum after collision.

Now applying this law for the above problem we get

Momentum before collision= momentum after collision.

Momentum before collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s

Momentum after collision = (m1+m2+m3) x v2 =(225+180+150)x v2

=555v2

Now we know that Momentum before collision= momentum after collision.

Hence we get

1215 = 555 v2

v2 = 2.188 m/s

Hence the velocity of the combined bumper cars is 2.188 m/s

4 0

1 year ago

Read 2 more answers

A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w

Aloiza [94]

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

4 0

1 year ago

A windowpane is half a centimeter thick and has an area of 1.0 m2. The temperature difference between the inside and outside sur

polet [3.4K]

To solve this problem it is necessary to apply the concepts related to the heat flux rate expressed in energetic terms. The rate of heat flow is the amount of heat that is transferred per unit of time in some material. Mathematically it can be expressed as:

$\frac{Q}{t} = \frac{kA}{L} (T_H - T_C)$

Where

k = 0.84 J/s⋅m⋅°C (The thermal conductivity of the material)

$A = 1m^2$ Area

$L = 5*10^{-3}m$ Length

$T_H$ = Temperature of the "hot"reservoir

$T_C$ = Temperature of the "cold"reservoir

Replacing with our values we have that,

$\frac{Q}{t} = \frac{kA}{L} (T_H - T_C)$

$\frac{Q}{t} = \frac{(0.84)(1)}{0.005} (15)$

$\frac{Q}{t} = 2520J/s$

Therefore the correct answer is B.

3 0

1 year ago

one horsepower is a unit of power equal to 746w. how much energy can a 150-horsepower engine transform in 10.0s?

Dafna1 [17]

1 watt = 1 joule/second

1 horsepower = 746 watts = 746 joule/second

(150 horsepower) x (746 watt/HP) x (1 joule/sec / watt) x (10 sec)

= (150 x 746 x 1 x 10) joule = 1,119,000 joules .
if correct plz mark brainly

8 0

1 year ago

A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly hori

Nutka1998 [239]

Answer:

The cannonball fly horizontally before it strikes the ground, S = 323.25 m

Explanation:

Given data,

The height of the cliff, h = 80 m

The horizontal velocity of the cannonball, Vₓ = 80 m/s

The range of the cannon ball with initial vertical velocity is zero is given by the formula,

$S=\frac{V_{x}\sqrt{2gh}}{g}$