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Vitek1552 [10]
2 years ago
11

Plants breathe in carbon dioxide to make sugar through photosynthesis. How much sugar can they create if 200 grams of carbon dio

xide are used ?6 CO2 + 6 H2O -> C6H12O6 + 6 O2
Chemistry
1 answer:
Lady bird [3.3K]2 years ago
4 0

Answer:

\boxed{\text{136 g}}

Explanation:

We will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:   44.01                      180.16

          6CO₂ + 6H₂O ⟶ C₆H₁₂O₆ + 6O₂

m/g:    200

1. Moles of CO₂

\text{Moles of CO}_{2} = \text{200 g CO}_{2} \times \dfrac{\text{1 mol CO}_{2}}{\text{ 44.01g CO}_{2}} = \text{4.54 mol CO}_{2}

2. Moles of C₆H₁₂O₆

The molar ratio is 1 mol C₆H₁₂O₆:6 mol CO₂

\text{Moles of C$_{6}$H$_{12}$O}_{6} =\text{4.54 mol CO}_{2} \times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{6 mol CO}_{2}} = \text{0.757 mol C$_{6}$H$_{12}$O}_{6}

3. Mass of C₆H₁₂O₆

\text{Mass of C$_{6}$H$_{12}$O}_{6} = \text{0.757 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} =\textbf{136 g C$_{6}$H$_{12}$O}_{6}\\\\\text{The plants can create }\boxed{\textbf{136 g C$_{6}$H$_{12}$O}_{6}}

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A column is filled with four different liquids of different densities. A red liquid, a blue liquid, a green liquid, and a purple
Svet_ta [14]

<em>Answer:</em>

The order of liquid from top to bottom is as follow

  •        Purple, green, red, blue

<em>Explanation:</em>

Chart of densities:

  •   Red = 1.2 g/cm∧3
  •   Blue = 1.6 g/cm∧3
  •   green = 0.8 g/cm∧3
  •   Purple = 0.1 g/cm∧3

<em>Density:   </em>

Density is the ratio of mass and volume as follow

                             d = m/v

<em>Summary:</em>

  • Greater the density, it will be at bottom and vice versa.
  • Blue liquid has greater density so it will be at bottom
  • Purple liquid has low density, so it will be at top.
5 0
2 years ago
Read 2 more answers
A 23.2 g sample of an organic compound containing carbon, hydrogen and oxygen was burned in excess oxygen and yielded 52.8 g of
allochka39001 [22]

Answer:

The answer to your question is   C₃H₆O

Explanation:

Data

mass of sample = 23.2 g

mass of carbon dioxide = 52.8 g

mass of water = 21.6 g

empirical formula = ?

Process

1.- Calculate the mass and moles of carbon

                       44 g of CO₂ ---------------  12 g of C

                        52.8 g          ---------------  x

                        x = (52.8 x 12)/44

                        x = 633.6/44

                        x = 14.4 g of C

                        12 g of C ------------------  1 mol

                        14.4 g of C ---------------   x

                         x = (14.4 x 1)/(12)

                         x = 1.2 moles of C

2.- Calculate the grams and moles of Hydrogen

                         18 g of H₂O ---------------  2 g of H

                         21.6 g of H₂O -------------  x

                          x = (21.6 x 2) / 18

                         x = 2.4 g of H

                         1 g of H -------------------- 1 mol of H

                         2.4 g of H -----------------  x

                          x = (2.4 x 1)/1

                          x = 2.4 moles of H

3.- Calculate the grams and moles of Oxygen

Mass of Oxygen = 23.2 - 14.4 - 2.4

                           = 6.4 g

                         16 g of O ----------------  1 mol

                          6.4 g of O --------------  x

                          x = (6.4 x 1)/16

                          x = 0.4 moles of Oxygen

4.- Divide by the lowest number of moles

Carbon = 1.2 / 0.4 = 3

Hydrogen = 2.4/ 0.4 = 6

Oxygen = 0.4 / 0.4 = 1

5.- Write the empirical formula

                                C₃H₆O

8 0
2 years ago
in a candy factory, the nutty chocolate bars contain 22.0% by mass pecans. If 5.0 kg of pecans were used for candy last Tuesday,
zysi [14]
22.0 is the same as saying that in 100 grams of a chocolate bar, there are 22.0 grams of pecans. or to make it easier because of this problem- 100 Kilograms of a chocolate bar, there is 22.0 Kg of pecans. we can use this as a conversion factor (what is used to convert a value to another value. 

conversion factor---> 22.0 kg of pecan= 100 kg of chocolate bar
Note: remember this, what you are converting from goes in the denominator, what you converting to goes in the numerator. 

5.0 Kg of pecan (100 Kg of chocolate bar/ 22.0 Kg of pecan)= 23 Kg of chocolate bar


7 0
2 years ago
in sample of elemental bromine, 55% or the atoms are Br-79, and the remainder are Br-81. if this sample is typical of naturally
Gwar [14]

Answer:

The average atomic mass of bromine is 79.9 amu.

Explanation:

Given data:

Percentage of Br⁷⁹ = 55%

Percentage of Br⁸¹ = 45%

Average atomic mass of bromine = ?

Formula:

Average atomic mass = [mass of isotope× its abundance] + [mass of isotope× its abundance] +...[ ] / 100

Now we will put the values in formula.

Average atomic mass = [55 × 79] + [81 ×45] / 100

Average atomic mass = 4345 + 3645 / 100

Average atomic mass = 7990 / 100

Average atomic mass = 79.9 amu

The average atomic mass of bromine is 79.9 amu.

3 0
2 years ago
Write the balanced chemical equation for the reaction shown.
son4ous [18]

Explanation:

        Carbon                  black sphere

        Nitrogen                blue sphere

        Chlorine                green sphere

        Hydrogen              white sphere

 Reactants:

  three molecules that contain one black sphere and four white spheres

           3CH₄

three molecules that contain two blue spheres and four green spheres:

           3N₂Cl₄

Products:

 three molecules that contain one black sphere and four green spheres:

           3CCl₄

 three molecules that contain two blue spheres:

            3N₂

   six molecules that contain two white spheres

            6H₂

The reaction proper:

                    3CH₄ +      3N₂Cl₄  →   3CCl₄ + 3N₂ + 6H₂

Learn more:

Chemical reactions  brainly.com/question/4216541

#learnwithBrainly

7 0
2 years ago
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