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inn [45]
1 year ago
9

A machine is currently set to a feed rate of 5.921 inches per minute (IPM). Te machinist changes this setting to 6.088 IPM. By h

ow much did the machinist increase the feed rate
Physics
2 answers:
LekaFEV [45]1 year ago
6 0

Explanation:

Given that,

Current feed rate of a machine is 5.921 IPM

Final feed rate of the machine is 6.088 IPM

To find,

Increase in feed rate

Solution,

We need to find the increase in feed rate of the machine. It is calculated simply by subtracting final feed rate to the initial feed rate as :

Increase in feed rate = 6.088 IPM - 5.921 IPM

Increase in feed rate = 0.167 IPM

or

Increase in feed rate = 16.7 %

So, the increase in feed rate of the machine is 0.167 IPM or 16.7 %

lukranit [14]1 year ago
4 0

Answer:

By 16.7% or 0.167 IPM

Explanation:

Substracting the final IPM (6.088) to the initial IPM (5.921) gives us the net difference, which is how much did it increase in IPM. Multiplying this number by 100 gives us the percentual increase in the feed rate.

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The water level in a tank is 20 m above the ground. a hose is connected to the bottom of the tank, and the nozzle at the end of
Damm [24]

Answer:

P_(pump) = 98,000 Pa

Explanation:

We are given;

h2 = 30m

h1 = 20m

Density; ρ = 1000 kg/m³

First of all, we know that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,

Thus, it can be expressed as;

P_(tank)+ P_(pump) = P_(nozzle)

Now, the pressure would be given by;

P = ρgh

So,

ρgh_1 + P_(pump) = ρgh_2

Thus,

P_(pump) = ρg(h_2 - h_1)

Plugging in the relevant values to obtain;

P_(pump) = 1000•9.8(30 - 20)

P_(pump) = 98,000 Pa

5 0
1 year ago
Cass is walking her dog (Oreo) around the neighborhood. Upon arriving at Calina's house (a friend of Oreo's), Oreo turns part mu
MArishka [77]

Answer:

Horizontal component: F_x = 58\ N

Vertical component: F_y = 33.5\ N

Explanation:

To find the horizontal and vertical components of the force, we just need to multiply the magnitude of the force by the cosine and sine of the angle with the horizontal, respectively.

Therefore, for the horizontal component, we have:

F_x = F * cos(angle)

F_x = 67 * cos(30)

F_x = 58\ N

For the vertical component, we have:

F_y = F * sin(angle)

F_y = 67 * sin(30)

F_y = 33.5\ N

So the horizontal component of the tension force is 58 N and the vertical component is 33.5 N.

4 0
1 year ago
The speed of sound in seawater is 1470 m/s. A dolphin sends out a click that reflects off of an
Nitella [24]

Answer: 0.204 s

Explanation:

The speed of sound V is defined as the distance traveled d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=1470 m/s is the speed of sound  in seawater

t is the time the sound wave travels from the dolphin and then returns after the reflection

d=2(150 m) is twice the distance between the dolphin and the object to which the sound waves are reflected

Finding t:

t=\frac{d}{V}  

t=\frac{2(150 m)}{1470 m/s}

<u>Finally:</u>

t=0.204 s

3 0
2 years ago
Current X is 2.5 A and runs for 39 seconds. Current Y is 3.8 A and runs for 24 seconds. Which current delivered more charge, and
Aleonysh [2.5K]

Answer: B. Current x delivered 6.3 C more then Y

Explanation:

7 0
2 years ago
A damped harmonic oscillator consists of a block of mass 2.5 kg attached to a spring with spring constant 10 N/m to which is app
Cerrena [4.2K]

Answer:

0.5% per oscillation

Explanation:

The term 'damped oscillation' means an oscillation that fades away with time. For Example; a swinging pendulum.

Kinetic energy, KE= 1/2×mv^2-------------------------------------------------------------------------------------------------------------(1).

Where m= Mass, v= velocity.

Also, Elastic potential energy,PE=1/2×kX^2----------------------------------------------------------------------------------------------------------------------(2).

Where k= force constant, X= displacement.

Mechanical energy= potential energy (when a damped oscillator reaches maximum displacement).

Therefore, we use equation (3) to get the resonance frequency,

W^2= k/m--------------------------------------------------------------------------------------(3)

Slotting values into equation (3).

= 10/2.5.

= ✓4.

= 2 s^-1.

Recall that, F= -kX

F^2= (-0.1)^2

Potential energy,PE= 1/2 ×0.01

Potential energy= 0.05 ×100

= 0.5% per oscillation.

6 0
1 year ago
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