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Mama L [17]
2 years ago
4

Two sound waves traveling in the same medium interfere with each other. The compression of one wave falls on the compression of

the other wave. What can you say about the resultant sound?
The resultant sound will be louder than the individual sound waves.
The resultant sound will be lower than the individual sound waves.
The resultant sound will have the same loudness as the individual sound waves.
The resultant sound will not be heard at all.
Physics
2 answers:
9966 [12]2 years ago
8 0

Answer: The correct answer is the resultant sound will be louder than the individual sound waves.

Explanation:

There are two types of interference which happens when two waves interact:

1. Constructive interference: In this type of interference, the two waves superimpose to form a resultant wave which has greater amplitude. The amplitude of the waves gets added up.

2. Destructive interference: In this type of interference, the two waves superimpose to form a resultant wave which has lower amplitude. The amplitude of the waves gets subtracted.

In the given question, the two waves are interacting and compression of one wave falls on another wave. Hence, they are undergoing a constructive interference.

So, the resultant sound will be louder than the individual sound waves.

Kryger [21]2 years ago
4 0
The correct answer among all the other choices is "The resultant sound will be louder than the individual sound waves." Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
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Explanation:

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2 years ago
You start with spring that's already been stretched an unknown amount from equilibrium. After stretching it an additional 2.0 cm
maxonik [38]

Answer: 35*10^3 N/m

Explanation: In order to explain this problem we know that the potential energy for spring is given by:

Up=1/2*k*x^2 where k is the spring constant and x is the streching or compresion position from the equilibrium point for the spring.

We  also know that with additional streching of 2 cm of teh spring,  the potential energy is 18J. Then it applied another additional streching of 2 cm and the energy is 25J.

Then the difference of energy for both cases is 7 J so:

ΔUp= 1/2*k* (0.02)^2 then

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7 0
2 years ago
It takes a slug 20 minutes to travel from the grass to the trash can , a trip of 15 meters. How far could the slug travel in 60
inn [45]

Answer:

45 meters

Explanation:

20 min = 15 meters

So if 20 x 3 = 60

you have to do 3 x 15 !

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5 0
2 years ago
A solenoid that is 35 cm long and contains 450 circular coils 2.0 cm in diameter carries a 1.75-A current. (a) What is the magne
Taya2010 [7]

Answer:

Explanation:

a )  No of turns per metre

n = 450 / .35

= 1285.71

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B = μ₀ n I

Where I is current

B = 4π x 10⁻⁷ x 1285.71 x 1.75

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This is the uniform magnetic field inside the solenoid.

b )

Magnetic field around a very long wire at a distance d is given by the expression

B = ( μ₀ /4π ) X 2I / d

= 10⁻⁷ x 2 x ( 1.75 / .01 )

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6 0
2 years ago
Read 2 more answers
14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?
Vladimir79 [104]
The relationship between resistance R and resistivity \rho is
R= \frac{\rho L}{A}
where L is the length of the wire and A its cross section.

The radius of the wire is half the diameter:
r= \frac{d}{2}= \frac{1.6 mm}{2}=0.8 mm=8\cdot 10^{-4} m
and the cross section is
A=\pi r^2 = \pi (8\cdot 10^{-4} m)^2=2.01\cdot 10^{-6} m^2

From the first equation, we can then find the length of the wire when R=4.8 \Omega (copper resistivity: \rho = 1.724 \cdot 10^{-8} \Omega m)
L= \frac{AR}{\rho}= \frac{(2.01\cdot 10^{-6} m^2)(1.724 \cdot 10^{-8} \Omega m)}{4.8 \Omega}=7.21 \cdot 10^{-15} m
4 0
2 years ago
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