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MissTica
2 years ago
8

The local meteorologist claims that the temperature is going to steadily drop over the next 4 hours. If the temperature changes

by the same amount each hour, and it changes by a total of -28°F, how much will it change each hour? Explain how you got your answer in two or more complete sentences.
Physics
2 answers:
Ad libitum [116K]2 years ago
3 0

Answer:

-7 ºF each hour

Explanation:

The problem says that in a total amount of 4 hours the total temperature drop is 28 ºF. We are asked to obtain how many Fahrenheit degrees drop each hour. To obtain the temperature, we just need to divide the total drop temperature by the total amount of time.

T[F]= 28 F/4 hrs

The result is 7 ºF. The minus sign is simply written to depict a decrease in temperature.

Allisa [31]2 years ago
3 0

-7 ºF each hour

Explanation:

The problem says that in a total amount of 4 hours the total temperature drop is 28 ºF. We are asked to obtain how many Fahrenheit degrees drop each hour. To obtain the temperature, we just need to divide the total drop temperature by the total amount of time.

The result is 7 ºF. The minus sign is simply written to depict a decrease in temperature.

Explanation:

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AleksandrR [38]

Answer:

Explanation:

For the problem, we should have same reynolds number

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1000×1×10⁻³×0.3×10⁻³/1.002×10⁻³ = 1400×0.5×d/600

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2 years ago
For a group class project, students are building model roller coasters. Each roller coaster needs to begin at the top of the fir
abruzzese [7]

Case A :

A .75 kg 65 N/m 1.2 m

m = mass of car = 0.75 kg

k = spring constant of the spring = 65 N/m

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Using conservation of energy between Top of hill and Bottom of hill

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(0.5) k x² + mgh = (0.5) m v²

(0.5) (65) (0.25)² + (0.75 x 9.8 x 1.2) = (0.5) (0.75) v²

v = 5.4 m/s



Case B :

B .60 kg 35 N/m .9 m

m = mass of car = 0.60 kg

k = spring constant of the spring = 35 N/m

h = height of the hill = 0.9 m

x = compression of spring = 0.25 m

Using conservation of energy between Top of hill and Bottom of hill

Total energy at Top of hill = Total energy at Bottom of hill

spring energy + potential energy = kinetic energy

(0.5) k x² + mgh = (0.5) m v²

(0.5) (35) (0.25)² + (0.60 x 9.8 x 0.9) = (0.5) (0.60) v²

v = 4.6 m/s




Case C :

C .55 kg 40 N/m 1.1 m

m = mass of car = 0.55 kg

k = spring constant of the spring = 40 N/m

h = height of the hill = 1.1 m

x = compression of spring = 0.25 m

Using conservation of energy between Top of hill and Bottom of hill

Total energy at Top of hill = Total energy at Bottom of hill

spring energy + potential energy = kinetic energy

(0.5) k x² + mgh = (0.5) m v²

(0.5) (40) (0.25)² + (0.55 x 9.8 x 1.1) = (0.5) (0.55) v²

v = 5.1 m/s




Case D :

D .84 kg 32 N/m .95 m

m = mass of car = 0.84 kg

k = spring constant of the spring = 32 N/m

h = height of the hill = 0.95 m

x = compression of spring = 0.25 m

Using conservation of energy between Top of hill and Bottom of hill

Total energy at Top of hill = Total energy at Bottom of hill

spring energy + potential energy = kinetic energy

(0.5) k x² + mgh = (0.5) m v²

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v = 4.6 m/s


hence closest is in case C at 5.1 m/s




7 0
2 years ago
Read 2 more answers
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of t
Juliette [100K]

Answer:

24.348mm

Explanation:

NB: I'll be attaching pictures so as to depict missing mathematical expressions or special characters which are not easily found on keyboards

K = d / €^n

Note : d represents the greek alphabet epsilion.

K = 345 / 0.02⁰.²² = 816mPa

The true strain based upon the stress of 414mPa =

€= (€/k)^1/n = (414/816)¹/⁰.²² = 0.04576

However the true relationship between true strain and length is given by

€ = ln(Li/Lo)

Making Li the subject of formula by rearranging,

Li = Lo.e^€

Li = 520e⁰.⁰⁴⁵⁷⁶

Li = 544.348mm

The amount of elongation can be calculated from

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8 0
2 years ago
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Rufina [12.5K]

Answer:

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α =0.0002m /(0.2m * 99ºC)

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4 0
2 years ago
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Masja [62]
Is  D    the  right  answer
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