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sesenic [268]
2 years ago
11

The image shows a pendulum that is released from rest at point A. Shari tells her friend that no energy transformation occurs as

the pendulum swings between point B and point D.
What is the best response that Shari’s friend could make?

She could agree with Shari because the pendulum is at the same height and would have the same gravitational potential energy at both positions.

She could agree with Shari because the pendulum has the same amount of mechanical energy throughout its swing.

She could disagree with Shari because the pendulum converts kinetic energy into gravitational potential energy, then back into kinetic energy.

She could disagree with Shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.

Physics
2 answers:
Masja [62]2 years ago
6 0
Is  D    the  right  answer
OlgaM077 [116]2 years ago
5 0

Answer:

She could disagree with Shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.

Explanation:

The energy of the pendulum is constantly converted from gravitational potential to kinetic, and back.

In fact:

- the gravitational potential energy of the pendulum is given by:

U=mgh

where m is the mass of the pendulum, g is the gravitational acceleration, and h is the height of the pendulum above the ground

- The kinetic energy of the pendulum is given by:

K=\frac{1}{2}mv^2

where v is the speed of the pendulum.

Therefore, when it is at a higher position, the pendulum has a greater potential energy, while when it is at a lower position, the pendulum has a greater kinetic energy (because its speed is higher).

In this example:

- when the pendulum swings from B to C, part of its gravitational potential energy is converted into kinetic energy (because the height decreases but the speed increases), and when the pendulum goes from C to D, the kinetic energy is converted back into gravitational potential energy (because the height increases and the speed decreases)

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A 56 kg diver runs and dives from the edge of a cliff into the water which is located 4.0 m below. If she is moving at 8.0 m/s t
Reil [10]

Answer:

1) 2197.44 J

2) 0 J

3) 2197.44 J = Constant

4) 2197.44 J

5) Approximately 8.86 m/s

Explanation:

The given parameters are;

The mass of the diver, m = 56 kg

The height of the cliff, h = 4.0 m

The speed with which the diver is moving, vₓ = 8.0 m/s

The gravitational potential energy = Mass, m × Height of the cliff, h × Acceleration due to gravity, g

1) Her gravitational potential energy = 56 × 4.0 × 9.81 = 2197.44 J

2) The kinetic energy = 1/2·m·u²

Where;

u = Her initial velocity = 0 when she just leaves the cliff

Therefore;

Her kinetic energy when she just leaves the cliff = 1/2 × 56 × 0² = 0 J

3) The total mechanical energy = Kinetic energy + Potential energy

The total mechanical energy is constant

Her total mechanical energy relative to the water surface when she leaves the cliff = Her gravitational potential energy = 2197.44 J = Constant

4) Her total mechanical energy relative to the water surface just before she enters the water = 2197.44 J

5) The speed with which she enters the water, v, is given from, v² = u² + 2·g·h

Where;

u = The initial velocity at the top of the cliff before she jumps= 0 m/s

∴ v² = 0² + 2 × 9.81 × 4 = 78.48

v = √78.48 ≈ 8.86 m/s

The speed with which she enters the water, v ≈ 8.86 m/s

7 0
2 years ago
Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of
Sonbull [250]
The formula is Ke = 1/2 m v^2
The two of them together have a Ke of mv^2. So you either increase m or v. That's what makes the problem difficult. He can do D or B. We have to choose.

A is no solution. The Ke goes down because Paul loses Ivan's mass.
C is out of the question 3 meters/sec is a big reduction from 5 m/s. So now what do we do about B and D?

The question is what does the third person add. The tandoms I've peddled only allow for 1 or 2 people to add to the motion. So the third person only adds mass. He does not have a v that he is contributing to. To say that he is going 5m/s is true, but he's not contributing anything to that motion.

I pick B, but it is one of those questions that the correctness of it is in the head of the proposer. Be prepared to get it wrong. Argue the point politely if you agree with me, but back off as soon as you have presented your case.

B <<<<====== answer. 
5 0
2 years ago
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A car travels straight for 20 miles on a road that is 30° north of east. What is the east component of the car’s displacement to
Virty [35]
17.3 would be the correct answer.

4 0
2 years ago
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Suppose I have an infinite plane of charge surrounded by air. What is the maximum charge density that can be placed on the surfa
gregori [183]

Answer:

53.1\mu C/m^2

Explanation:

We are given that

Electric field,E=3\times 10^6V/m

We have to find the value of maximum charge density that can be placed on the surface of the plane before dielectric breakdown of the surrounding air occurs.

We know that

E=\frac{\sigma}{2\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}

Using the formula

3\times 10^6=\frac{\sigma}{2\times 8.85\times 10^{-12}}

\sigma=3\times 10^6\times 2\times 8.85\times 10^{-12}

\sigma=5.31\times 10^{-5}C/m^2

\sigma=53.1\times 10^{-6}C/m^2=53.1\mu C/m^2

1\mu C=10^{-6} C

3 0
2 years ago
A fish is 80 cm below the surface of a pond. What is the apparent depth (in cm) when viewed from a position almost directly abov
Rudik [331]

Answer:

Apparent depth (Da) = 60.15 cm (Approx)

Explanation:

Given:

Distance from fish (D) = 80 cm

Find:

Apparent depth (Da)

Computation:

We know that,

Refractive index of water (n2) = 1.33

So,

Apparent depth (Da) = D(n1/n2)

Apparent depth (Da) = 80 (1/1.33)

Apparent depth (Da) = 60.15 cm (Approx)

5 0
2 years ago
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