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sesenic [268]
2 years ago
11

The image shows a pendulum that is released from rest at point A. Shari tells her friend that no energy transformation occurs as

the pendulum swings between point B and point D.
What is the best response that Shari’s friend could make?

She could agree with Shari because the pendulum is at the same height and would have the same gravitational potential energy at both positions.

She could agree with Shari because the pendulum has the same amount of mechanical energy throughout its swing.

She could disagree with Shari because the pendulum converts kinetic energy into gravitational potential energy, then back into kinetic energy.

She could disagree with Shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.

Physics
2 answers:
Masja [62]2 years ago
6 0
Is  D    the  right  answer
OlgaM077 [116]2 years ago
5 0

Answer:

She could disagree with Shari because the pendulum converts gravitational potential energy into kinetic energy, then back into gravitational potential energy.

Explanation:

The energy of the pendulum is constantly converted from gravitational potential to kinetic, and back.

In fact:

- the gravitational potential energy of the pendulum is given by:

U=mgh

where m is the mass of the pendulum, g is the gravitational acceleration, and h is the height of the pendulum above the ground

- The kinetic energy of the pendulum is given by:

K=\frac{1}{2}mv^2

where v is the speed of the pendulum.

Therefore, when it is at a higher position, the pendulum has a greater potential energy, while when it is at a lower position, the pendulum has a greater kinetic energy (because its speed is higher).

In this example:

- when the pendulum swings from B to C, part of its gravitational potential energy is converted into kinetic energy (because the height decreases but the speed increases), and when the pendulum goes from C to D, the kinetic energy is converted back into gravitational potential energy (because the height increases and the speed decreases)

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A DJ starts up her phonograph player. The turntable accelerates uniformly from rest, and takes t1 = 11.9 seconds to get up to it
Degger [83]

Answer:

a)\omega_1=8.168\,rad.s^{-1}

b)n_1=7.735 \,rev

c)\alpha_1 =0.6864\,rad.s^{-2}

d)\alpha_2=4.1454\,rad.s^{-2}

e)t_2=1.061\,s

Explanation:

Given that:

  • initial speed of turntable, N_0=0\,rpm\Rightarrow \omega_0=0\,rad.s^{-1}
  • full speed of rotation, N_1=78 \,rpm\Rightarrow \omega_1=\frac{78\times 2\pi}{60}=8.168\,rad.s^{-1}
  • time taken to reach full speed from rest, t_1=11.9\,s
  • final speed after the change,  N_2=120\,rpm\Rightarrow \omega_2=\frac{120\times 2\pi}{60}=12.5664\,rad.s^{-1}
  • no. of revolutions made to reach the new final speed,  n_2=11\,rev

(a)

∵ 1 rev = 2π radians

∴ angular speed ω:

\omega=\frac{2\pi.N}{60}\, rad.s^{-1}

where N = angular speed in rpm.

putting the respective values from case 1 we've

\omega_1=\frac{2\pi\times 78}{60}\, rad.s^{-1}

\omega_1=8.168\,rad.s^{-1}

(c)

using the equation of motion:

\omega_1=\omega_0+\alpha . t_1

here α is the angular acceleration

78=0+\alpha_1\times 11.9

\alpha_1 = \frac{8.168 }{11.9}

\alpha_1 =0.6864\,rad.s^{-2}

(b)

using the equation of motion:

\omega_1\,^2=\omega_0\,^2+2.\alpha_1 .n_1

8.168^2=0^2+2\times 0.6864\times n_1

n_1=48.6003\,rad

n_1=\frac{48.6003}{2\pi}

n_1=7.735\, rev

(d)

using equation of motion:

\omega_2\,^2=\omega_1\,^2+2.\alpha_2 .n_2

12.5664^2=8.168^2+2\alpha_2\times 11

\alpha_2=4.1454\,rad.s^{-2}

(e)

using the equation of motion:

\omega_2=\omega_1+\alpha_2 . t_2

12.5664=8.168+4.1454\times t_2

t_2=1.061\,s

4 0
2 years ago
There are many ways to lose weight, but a sustainable plan generally involves behavior modification related to diet and exercise
Anna007 [38]

The answer is adequate nutrition, regular physical activity, and practical ways to reduce calories while retaining important nutrients.

Explanation:

Despite that adequate nutrition, regular physical activity, and practical ways to reduce calories while retaining important nutrients is one of the best strategy to reducing weight, most time it is very difficult for those that want to reduce or control their weight to discipline themselves enough to follow these routine. But one an individual that want to loose weight or live a healthy lifestyle is able to follow these procedures he/she will surely loose weight.

5 0
2 years ago
A toy plane has a mass of 2.5 kg and is 18 m above the ground. It is moving at 4.5 m/s. How much mechanical energy does the toy
sleet_krkn [62]
Mechanical energy is the sum of kinetic energy and potential energy, or E=Ek+Ep. So Ek=(1/2)*m*v² where m is the mass of the object and v is it's velocity. Mp=m*g*h where m is the mass, g=9.81 m/s² and h is the height of the object. So after we input the numbers the total mechanical energy is
E=(1/2)*2.5*(4.5²) + 2.5*9.81*18 = 25.3125 J + 441.45 J = 466.7625 J. The correct answer is E= 466 J. 
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2 years ago
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Utility poles are to be set every 30 meters. How many poles will be set in one mile if one was set at the beginning of the mile)
Zepler [3.9K]

Answer:

53

Explanation:

Because there are 1609.34 meters in a mile. 1609.34÷30=53.64 but because you put one at the beginning of the mile it will stay 53 and not round up to 54

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Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he
olga2289 [7]
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency. 

Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by
\eta = 1- \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the cold temperature
T_{hot} is the hot temperature

For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
\eta=1- \frac{313 K}{425 K}=0.264 = 26.4 \%
3 0
2 years ago
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