Question

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5\,\dfrac{\text m}{\text s^2}0.5 s 2 m ​ 0, point, 5, space, start fraction, m, divided by, s, start superscript, 2, end superscript, end fraction for 3\,\text s3s3, space, s. After the wind stops, the bird is flying to the right with a velocity of 2.5\,\dfrac{\text m}{\text s}2.5 s m ​ 2, point, 5, space, start fraction, m, divided by, s, end fraction.

Answer 1

The initial velocity of the bird before the gust of wind : 4 m/s

Further explanation

An equation of uniformly accelerated motion  

$\large {\boxed {\bold {x = xo + vo.t + \frac {1} {2} at ^ 2}}}$

v = vo + at  

Vt² = vo² + 2a (x-xo)  

x = distance on t  

vo/vi = initial speed  

vt/vf = speed on t /final speed

a = acceleration  

Acceleration is a change in speed within a certain time interval  

a = Δv /Δ t  

$\displaystyle a=\frac{v2-v1}{t2-t1}$

Let complete the task :

A bird is flying to the right when a gust of wind causes the bird to accelerate leftward at 0.5 m/s² for 3 s. After the wind stops, the bird is flying to the right with a velocity of 2.5 m/s.

Assuming the acceleration from the wind is constant, what was the initial velocity of the bird before the gust of wind?

we can use formula :

vf = vi + a.t

vf = final velocity = 2.5 m/s

vi = asked

a = - 0.5 m/s²(leftward=negative)

t = 3 s

then :

$\displaystyle 2.5=vi-0.5.3\\\\vi=2.5+1.5\\\\vi=\boxed{\bold{4\frac{m}{s}}}$

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Keywords: uniformly accelerated motion,  distance, velocity, acceleration

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