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Georgia [21]
2 years ago
7

The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least

Physics
2 answers:
Genrish500 [490]2 years ago
8 0

Answer:

D, C, B, A

Explanation:

The derivative of a velocity-time graph will give you the acceleration.

Segment A

         \frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2

Segment B

         \frac{dy}{dx} = \frac{5m/s}{1s} = 5m/s^2

Segment C

         \frac{dy}{dx} = \frac{0m/s}{2s} = 0m/s^2

Segment D

         \frac{dy}{dx} = \frac{-20m/s}{1s} = -20m/s^2

From least to greatest acceleration:

         D, C, B, A

aliya0001 [1]2 years ago
7 0

Segment D is -20 m/s squared

C

B

A

I know because I just did this

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Answer:

Number of photons travel through pin hole=6.4*10^{17}

Explanation:

First we will calculate the energy of single photon using below formula:

E=\frac{h*c}{λ}

Where :

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c is the speed of light whch is3*10^{8}

λ is the wave length = 532nm

E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}

E=3.73*10^{-19}J

Number of photons emitted per second:

\frac{5J/s}{1 photon/3.73*10^{-19} }

Number of photons emitted per second=1.34*10^{19} photons/s

\frac{A-hole}{A-beam}=\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

\frac{A-hole}{A-beam}=\frac{d-hole^2}{d-beam^2}

\frac{Ahole}{A-beam}=\frac{1.22^2}{5.5^2}

\frac{A-hole}{A-beam}=\frac{144}{3025}

Number of photons travel through pin hole=1.34*10^{19} *\frac{144}{3025}

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2 years ago
What is the wavelength of a 100-mhz ("fm 100") radio signal?
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The free-body diagram of a crate is shown. What is the net force acting on the crate? 352 N to the left 176 N to the left 528 N
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As per given conditions there are two directions along which forces are acting

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2. Net force towards right direction is given as

F_{right} = 528N + 440 N = 968 N

now since the two forces here in opposite direction so here we will have net force given as

F_{net} = F_{right} - F_{left}

F_{net} = 968 - 528

F_{net} = 440 N

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2 years ago
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Helga [31]

Answer:

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Explanation:

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Required

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v = 10.149/0.2459

v = 41.27m/s

Hence the speed of the golf ball immediately after impact is 41.27m/s

8 0
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