Answer:
Number of photons travel through pin hole=
Explanation:
First we will calculate the energy of single photon using below formula:

Where :
h is plank's constant with value 
c is the speed of light whch is
λ is the wave length = 532nm

E=
J
Number of photons emitted per second:

Number of photons emitted per second=
=
Where:
A-hole is area of hole
A-beam is area of beam
d-hole is diameter of hole
d-beam is diameter if beam
=
=
=
Number of photons travel through pin hole=
Number of photons travel through pin hole=
Radio wave is about 3.10^8m/s divided by 10^8 hz is 3 nesters sound wave is 343m/s so thus Equal to approximately 0.78
As per given conditions there are two directions along which forces are acting
1. Net force along left direction is given as

2. Net force towards right direction is given as

now since the two forces here in opposite direction so here we will have net force given as



so here net forces must be 440 N towards right
Answer:
41.27m/s
Explanation:
According to law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the velocity after impact
Given
m1 = 0.2kg
u1 = 43.7m/s
m2 = 45.9g = 0.0459kg
u2 = 30.7m/s
Required
Velocity after impact v
Substitute the given parameters into the formula
0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v
8.74+1.409 = 0.2459v
10.149 = 0.2459v
v = 10.149/0.2459
v = 41.27m/s
Hence the speed of the golf ball immediately after impact is 41.27m/s