The correct question is
<span>Javier is making a cake for a party. The recipe calls for 2 3/4 cups of flour, but he wants to triple the recipe. He guessed and put in 7 cups of flour. How many more cups of flour should he have used?
we know that
2 3/4 cups of flour------> (2*4+3)/4----> 11/4 cups
if he </span>wants to triple the recipe------> 3*(11/4)----> 33/4 ----> 8 1/4 cups required
8 1/4-7=1 1/4 cups
the answer is
1 1/4 cups
$6.05 because 10.09 × 0.6 is 6.054, round down because the last number is less than 5, and you have 6.05.
Answer:
y2 = C1xe^(4x)
Step-by-step explanation:
Given that y1 = e^(4x) is a solution to the differential equation
y'' - 8y' + 16y = 0
We want to find the second solution y2 of the equation using the method of reduction of order.
Let
y2 = uy1
Because y2 is a solution to the differential equation, it satisfies
y2'' - 8y2' + 16y2 = 0
y2 = ue^(4x)
y2' = u'e^(4x) + 4ue^(4x)
y2'' = u''e^(4x) + 4u'e^(4x) + 4u'e^(4x) + 16ue^(4x)
= u''e^(4x) + 8u'e^(4x) + 16ue^(4x)
Using these,
y2'' - 8y2' + 16y2 =
[u''e^(4x) + 8u'e^(4x) + 16ue^(4x)] - 8[u'e^(4x) + 4ue^(4x)] + 16ue^(4x) = 0
u''e^(4x) = 0
Let w = u', then w' = u''
w'e^(4x) = 0
w' = 0
Integrating this, we have
w = C1
But w = u'
u' = C1
Integrating again, we have
u = C1x
But y2 = ue^(4x)
y2 = C1xe^(4x)
And this is the second solution
Answer:
there are 161 calories in 28 gram,then:
one gram of dry roasted cashews contains=161/28=5.75 calories
You eat 12 gram of it, =12*5.75=69 calories
9 cashews has 12gram, then:
one gram of dry roasted cashews contains= 9/12 = 0.75 cashews
there are total of 28gram in one serving.
Therefore cashews in one serving = 0.75*28=21cashews
a)69 calories
b)21cashews
49.50 because you take 35 plus 20 which equals 55, then subtract 10% and you get 49.5 so I then added a zero and got 49.50
