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Ivan
2 years ago
12

The compressibility factor of any gas at a specific value of reduced temperature, T Tc, and reduced pressure, P Pc does not have

approximately the same value for all species. Select one: True False
Chemistry
1 answer:
Ivahew [28]2 years ago
6 0

Answer:

False

Explanation:

According to principle of corresponding state, at reduced states or corresponding state, behavior of all gases are similar.

This principle is proposed by van der Waals.

In other words, all gases at same reduced temperature, reduced pressure and reduced volume deviate from ideal gas behavior to the same degree or have same compressibility factor.

Reduced quantities are defined as:

Reduced pressure P_R = \frac{P}{P_c}

Reduced temperature T_R = \frac{T}{T_c}

Reduced volume V_R = \frac{V}{V_c}

Where,

P_c = Critical pressure

V_c = Critical volume

T_c = Critical temperature

The compressibility factor (Z_c) at critical temperature is given by,

                                      Z_c=\frac{P_c V_c}{n_c k_B T_c}

Crtitical parameters (critical temperaures, critical pressure and critical volume) can be expressed in terms of van der Waals parameters a and b.

Principle of corresponding state can also be stated as gases at the same reduced pressure and reduced temperature have same reduced volume.

Hence, compressibility factor at reduced state will be same for all gase. so the given statement is false.

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You can identify a metal by carefully determining its density. A 8.44 g piece of an unknown metal is 1.25 cm long, 2.50 cm wide,
Dafna1 [17]

Answer: Aluminum, 2.70 g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.  It is characteristic of a substance.

Density=\frac{mass}{Volume}

Given : Mass of object = 8.44 grams

Volume of object=length\times breadth\times height=1.25cm\times 2.50cm\times 1.0cm=3.125cm^3

Putting in the values we get:

Density=\frac{8.44g}{3.125cm^3}=2.70g/cm^3

Thus density of the object will be 2.70 g/cm^3  which matches that of aluminium.

4 0
2 years ago
Read 2 more answers
Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen.
Debora [2.8K]

Answer:

The answer to your question is:       C₁₈ H₂₇ N O₃

Explanation:

Data

Carbon = 70.79 g

Hydrogen = 8.91 g

Nitrogen = 4.58 g

Oxygen = 15.72 g

Process

AT C = 12 g

AT H = 1 g

AT N = 14 g

AT O = 16 g

                   Carbon

                                  12 g ------------------------  1 mol

                           70.79  g -------------------------   x

                                 x = (70.79 x 1) / 12

                                 x = 5.9 mol of C

                  Hydrogen

                                   1 g -----------------------  1 mol

                                8.91 g ---------------------   x

                                  x = (8.91 x 1) / 1

                                  x = 8.91 mol of H

                  Nitrogen

                                 14 g ---------------------- 1 mol

                                4.58 g -------------------   x

                                   x = (4.58 x 1) / 14

                                   x = 0.33 mol

                  Oxygen

                               16 g ------------------------  1 mol

                               15.72 g --------------------   x

                                  x = (15.72 x 1)/16

                                 x = 0.98

Divide by the lowest number of moles

Carbon               5.9 / 0.33     =  17.9   ≈ 18

Hydrogen           8.91 /  0.33  =   27

Nitrogen             0.33 / 0.33  =    1

Oxygen               0.98 / 0.33 =    2.9  ≈ 3

                             C₁₈ H₂₇ N O₃

4 0
2 years ago
How many oxygen atoms are present in a 14.0 g sample of Cu(NO3)2
Vikentia [17]
<span>3 x 2 =6 oxygen atoms and multiply 6 by 14.0 and you have an answer. </span>
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2 years ago
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Okey so 1st find the moles of F2 which is :

n = 15/22.4 = 0.667mol

Then according to stoichiometric values, F2 and NaCl, they are to a ratio of 1 : 2

So take the twice value of the calculated moles.

Use the moles to find the mass using the equation :

m = n×M

Where m is the mass

n is moles

M is molar mass (of NaCl)

Therefore m = 1.334×57.5

(given the molar mass of Na 22gmol^-1 and CL 35.5gmol^-1)

m = 76.705g
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I think the answer would be that vegetable oil is a better conductor of heat than water.
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