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Firdavs [7]
1 year ago
12

A construction explosion has an intensity I of 1.25 x 10–4 W/m2. Find the loudness of the sound in decibels if W/m2. Round to th

e nearest tenth.
A. 81 decibels
B. 161 decibels
C. 82.2 decibels
D. 12.5 decibels
Mathematics
2 answers:
bezimeni [28]1 year ago
7 0
We solve this problem by using the decibels formula which is expressed as:

dB = 10 x log (Isig/Iref)

where dB is decibels, Isig is the intensity of the signal and Iref is the intentsity of the softest sound the human ear can hear which has a value of 10^-12.

We solve as follows:
dB = 10 x log (<span>1.25 x 10–4 </span>/ 10^-12 ) = 80.97 decibels

Therefore, the correct answer is option A, 81 decibels.
damaskus [11]1 year ago
4 0

Answer:

Step-by-step explanation:

1. B) logb(q^2t^8)

2. D) None of these (it is actually log (x^4/(x+2)^6) :D)

3. B) log5(7)+5log5(a)

4. C) 6.209

5. A) 81 decibels

You might be interested in
A population that consists of 500 observations has a mean of 40 and a standard deviation of 15. A sample of size 100 is taken at
Alex17521 [72]

Answer:

<h3>The option D) 1.50 is correct</h3><h3>That is the standard error of the sample mean is 1.50</h3>

Step-by-step explanation:

Given that a population that consists of 500 observations has a mean of 40 and a standard deviation of 15.

A sample size is 100  taken at random from the given population.

<h3>To find the standard error of the sample mean :</h3>

From the given Mean=40 and \sigma =15

For N=100

<h3>The formula for standard error is SE_{mean}=\frac{\sigma}{\sqrt{N}}</h3>

Substitute the values in the above formula we get

SE_{mean}=\frac{15}{\sqrt{100}}

=\frac{15}{10}

=1.50

∴ SE_{mean}=1.50

<h3>∴ The standard error of the sample mean is 1.50</h3><h3>Hence the option D) 1.50 is correct</h3>
7 0
2 years ago
After triangle ace is dilated by a factor of 5, it has an area of 100 square inches. What was its area before dilation?
NISA [10]

Answer:

20in^2

Step-by-step explanation:

Since you multiply the original area of the triangle by the scale factor to get the new area, you can find the original area (before dilation) by dividing the dilated triangle's area by the scale factor. Since 100 is the area of the dilated triangle, and 5 is your scale factor, you do 100/5 to get the area of the triangle before it was dilated.

5 0
1 year ago
A researcher is using a repeated-measures study to evaluate the difference between two treatments. If the difference between the
Leya [2.2K]

Answer:

A) a small variance for the difference scores and a small standard error

Step-by-step explanation:

Since the difference scores are obtained by subtracting one variable form another, if the difference scores are consistent between treatments, then the variance will be small. The higher the variance, the higher the standard error. So if the variance is small, then the standard error will also be small.

8 0
1 year ago
Cindi is planting a rectangular flower bed with 40 orange flower and 28 yellow flowers. She wants to plant them so that each row
Vilka [71]

Answer: 17 rows, 7 of yellow flowers and 10 of orange flowers.

Step-by-step explanation:

We have 40 orange flowers

we have 28 yellow flowers.

The total number of flowers is 40 + 28= 68

Now, we want to find the maximal comon factor between 28 and 40 (that will be the number of flowers in each row)

for this, we took the smallest number and find its factors, and then we see if those factors are also of the greater number.

28/1 = 28 ----> 40/28 is not integer, so 28 is not a factor of 40.

28/2 = 14 ----> 40/14 is not integer, so 14 is not a factor of 40.

28/3 is not integer.

28/4 = 7 ----> 40/7 is not integer, so 7 is not a factor of 40.

28/5 is not integer.

28/6 is not integer.

28/7 = 4, 40/4 = 10, so 4 is a factor of both 28 and 40.

Then the maximum number of flowers that we can put in each row is 4.

this means that we have:

28/4 = 7 rows of yellow flowers (with 4 flowers each)

40/4 = 10 rows of orange flowers (with 4 flowers each)

a total of 17 rows.

3 0
2 years ago
URGENT!! Please help Find the values of y=c(x) 3 square x, for x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, , 0.729 a
mojhsa [17]

Answer:

We have

$y=c(x)=\sqrt[3]{x} $

\text{for } x = 0, 0.008, 0.027, 0.064, 0.125, 0.216, 0.343, 0.512, 0.729 \text{ and } 1

We have 10 points to find:

\text{Point A}(0, 0)

\text{Point B}(0.008, 0.2)

\text{Point C}(0.027, 0.3)

\text{Point D}(0.064, 0.4)

\text{Point E}(0.125, 0.5)

\text{Point F}(0.216, 0.6)

\text{Point G}(0.343, 0.7)

\text{Point H}(0.512, 0.8)

\text{Point I}(0.729, 0.9)

\text{Point J}(1, 1)

4 0
1 year ago
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