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hjlf
2 years ago
13

A long, nonconducting cylinder (radius = 6.0 mm) has a nonuniform volume charge density given by αr2, where α = 6.2 mC/m5 and r

is the distance from the axis of the cylinder. What is the magnitude of the electric field at a point 2.0 mm from the axis?
Physics
1 answer:
erastovalidia [21]2 years ago
5 0

Answer: 2.80 N/C

Explanation: In order to calculate the electric firld inside the solid cylinder

non conductor we have to use the Gaussian law,

∫E.ds=Q inside/ε0

E*2πrL=ρ Volume of the Gaussian surface/ε0

E*2πrL= a*r^2 π* r^2* L/ε0

E=a*r^3/(2*ε0)

E=6.2 * (0.002)^3/ (2*8.85*10^-12)= 2.80 N/C

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What is the efficiency of a machine if your work on the machine is 1200 j and the machines output work is 300 j?
inysia [295]

Answer:

The efificiency is 0,25 of the machine  (25%). See the explanation below

Explanation:

We calculate the efficiency with this formula:

Efficiency = energy obtained/energy supplied= 300 Joule/1200 Joule

Efficiency= 0,25

Efficiency(%) = 0,25 x100 = 25%

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2 years ago
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Which equation is most likely used to determine the acceleration from a velocity vs:time graph?
tresset_1 [31]
Acceleration, a =  (v - u)/t

where v is the final velocity, u is the initial velocity, and t is the time.

This formula on a velocity time graph represents the slope of the graph.
 
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Burka [1]
Since this is a distance/time graph, the speed at any time is the slope
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At time  t1 = 2.0 s
That's in the middle of the first segment of the graph,
that extends from zero to 3 seconds.
Its slope is  7/3 .              v1 = 7/3 m/s .

At time  t2 = 4.0 s
That's in the middle of the horizontal part of the graph
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Its slope is zero.
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At time  t3 = 13 s.
That's in the middle of the part of the graph that's sloping down,
between 11 and 16 seconds.
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7 0
2 years ago
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Li is riding her bicycle at 8.0 m/s. She slows down to 4.0 m/s. Her change in velocity is m/s. If Li takes 2 seconds to make thi
forsale [732]
You will have to use this formula:
v = vo + a \times t

Final Velocity (V) = 4m/s
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Time (t) = 2 secs

Then:

-> 4 = 8 + a x 2
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Ps: It's value is negative because the she was in retrograde motion.

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4 0
2 years ago
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Now consider θc, the angle at which the blue refracted ray hits the bottom surface of the diamond. If θc is larger than the crit
Dennis_Churaev [7]

Complete Question:

A beam of white light is incident on the surface of a diamond at an angle \theta_{a},  since the index of refraction depends on the light's wavelength, the different colors that comprise white light will spread out as they pass through the diamond. For example, the indices of refraction in diamond are n_{red} = 2.410 for red light and n_{blue} = 2.450 for blue light. Thus, blue light and red light are refracted at different angles inside the diamond. The surrounding air has n_{air} = 1.000.

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\theta_{crit} = 24.09^{0}

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Only the blue refracted ray is related to the critical angle in this question

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The relationship between the critical angle(\theta_{crit}), n_{air} and n_{blue} can be given as sin \theta_{crit} = \frac{n_{air} }{n_{blue} }

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