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NeX [460]
2 years ago
13

You wad up a piece of paper and throw it into the wastebasket. How far will

Physics
2 answers:
vitfil [10]2 years ago
6 0

The range of the piece of paper is C) 1.4 m

Explanation:

The motion of the piece of paper is the motion of a projectile, which consists of two separate motions:

- A uniform motion along the horizontal direction, with constant velocity

- A uniformly accelerated motion along the vertical direction, with constant acceleration (the acceleration of gravity, g=9.8 m/s^2)

From the equation of motion, it is possible to find an expression for the range (the total horizontal distance covered) of a projectile, which is given by:

d=\frac{u^2 sin 2\theta}{g}

where

u is the initial velocity

\theta is the angle of projection

g is the acceleration of gravity

For the piece of paper in this problem,

u = 4.3 m/s

\theta=65^{\circ}

Substituting,

d=\frac{(4.3)^2 sin(2\cdot 65^{\circ})}{9.8}=1.45 m \sim 1.4 m

Learn more about projectile motion:

brainly.com/question/8751410

#LearnwithBrainly

aksik [14]2 years ago
4 0

Answer:

like the other person said, the answer is 1.4 m

Explanation:

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In a 1.25-T magnetic field directed vertically upward, a particle having a charge of magnitude 8.50μC and initially moving north
Goshia [24]

Answer:

a) The sign of the charge is positive.

b) The magnetic force on the particle is 0.050 newtons.

Explanation:

The magnetic force F on a moving charge with velocity v passing through a magnetic field B is:

\overrightarrow{F}=q\overrightarrow{v}\times\overrightarrow{B}(1)

a)

Because it is a cross product, we can find the direction of the force using the right-hand rule, that is too the direction of the movement. We have two possibilities here because the velocity vector and magnetic field are perpendicular: the particle deflects towards east or toward west, which depends on the charge of the particle. Note that if you put your right hand fingers, except thumb, pointing towards north (direction of velocity) and later close them in the direction of the magnetic field, if you maintain your thumb perpendicular to this movement it will point towards east (See figure), so that will be de direction of the force if the charge is positive, but if the charge is negative, the direction will be opposite (towards west). So the charge has to be positive to deflects towards east.

b)

Now by 1:

F=qvB\sin\theta=(8.50\times10^{-6})(4750)(1.25)\sin90\simeq\mathbf{0.050\,N}

5 0
2 years ago
As the external magnetic field decreases, an induced current flows in the coil. what is the direction of the induced magnetic fi
GrogVix [38]
As the external magnetic field decreases, an induced current flows in the coil. The direction of the induced magnetic field would be pointing to the screen. The flux through the coil is said to decrease. In order to counter this change, the coil would generate or produce a magnetic field that is induced that would be pointing to the same direction as the external field that is flowing which is into the the screen. This is according to Lenz's law or the right hand rule. It states that an induced current in a circuit that is due to the change or motion in   magnetic field should be directed opposing to the change in the flux.
4 0
2 years ago
A boat is headed with a velocity of 18 meters/second toward the last with respect to the water in the river. if the river is Flo
scoray [572]
In this case, the two vectors are in the same direction, so they simply add:

<span> total motion = 18m/s + 2.5m/s = 20.5m/s to the west </span>
8 0
2 years ago
Read 2 more answers
It's your birthday, and to celebrate you're going to make your first bungee jump. You stand on a bridge 110 m above a raging riv
zzz [600]

Answer:

h=20.66m

Explanation:

First we need the speed when the cord starts stretching:

V_2^2=V_o^2-2*g*\Delta h

V_2^2=-2*10*(-31)

V_2=24.9m/s   This will be our initial speed for a balance of energy.

By conservation of energy:

m*g*h+1/2*K*(h_o-l_o-h)^2-m*g*(h_o-l_o)-1/2*m*V_2^2=0

Where

h is your height at its maximum elongation

h_o is the height of the bridge

l_o is the length of the unstretched bungee cord

800h+21*(79-h)^2-63200-24800.4=0

21h^2-2518h+43060.6=0 Solving for h:

h_1=20.66m  and h_2=99.24m  Since 99m is higher than the initial height of 79m, we discard that value.

So, the final height above water is 20.66m

6 0
2 years ago
Read 2 more answers
In lab, your instructor generates a standing wave using a thin string of length L = 1.65 m fixed at both ends. You are told that
mars1129 [50]

Answer:

The maximum transverse speed of the bead is 0.4 m/s

Explanation:

As we know that the Amplitude of the travelling wave is

A = 3.65 mm

Now the speed of the travelling wave is

v_x = 13.5 m/s

now we know that distance of first antinode from one end is 27.5 cm

so length of the loop of the standing wave is given as

\frac{\lambda}{4} = 27.5 cm

\lambda = 110 cm

now we have

N = \frac{2L}{\lambda}

N = \frac{2(1.65)}{1.10}

N = 3

now we have

R = 2A sin(kx)

R = 2(3.65) sin(\frac{2\pi}{1.10}x)

R = 7.3 sin(1.82 \pi x)

now at x = 13.8 cm

R = 7.3 sin(1.82 \pi (0.138))

R = 5.18 mm

now we have

f = \frac{v}{\lambda}

f = \frac{13.5}{1.1}

f = 12.27 Hz

now maximum speed is given as

v_y = R\omega

v_y = (5.18 \times 10^{-3})(2\pi(12.27))

v_y = 0.4 m/s

4 0
1 year ago
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