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2 years ago

The solubility of cadmium cyanide is 1.70 g/100 mL of water at 25°C. Which of the following solutions is unsaturated?

Chemistry

1 answer:

hram777 [196]2 years ago

4 0

Answer:

The answer to your question is: letter B is correct

Explanation:

Calculate the Molarity of each solution an compare it to the solubility

Solubility

MW Cd(CN)2 = 252 g

252 g ---------------- 1 mol

1.7 g ------------------ x

x = (1.7 x1 ) / 252

x = 0.006 mol

Molarity = 0.006 / 0.1 = 0.067

a.97.0 g of Cd(CN)2 in 5.00 mL

252 g ---------------- 1 mol

97 g -------------------- x

x = (97 x 1) / 252

x = 0.38

Molarity = 0.38 / 0.005 =75 Saturated

b. 325.5 g of Cd(CN)2 in 20.5 L

252 g ---------------- 1 mol

325.5 g ---------------- x

x = (325.5 x 1) / 252

x = 1.29 mol

Molarity = 1.29 / 20.5 = 0.063 Unsaturated

c. No right answer.

d. 4.25 g of Cd(CN)2 in 250.0 mL

252 g ---------------- 1 mol

4.25 g --------------- x

x = (4.25 x 1) / 252

x = 0.017

Molarity = 0.017 / 0.25 = 0.067 Saturated

e. 5.750 g of Cd(CN)2 in 330.0 mL

252 g ---------------- 1 mol

5.75 g ------------------ x

x = (5.75 x 1) / 252 = 0.023

Molarity = 0.023 / 0.33 = 0.07 Saturated

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Answer:

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